結果

問題 No.2926 Botaoshi
ユーザー prin_kemkem
提出日時 2024-10-12 15:45:05
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 84 ms / 2,000 ms
コード長 1,263 bytes
コンパイル時間 200 ms
コンパイル使用メモリ 82,176 KB
実行使用メモリ 77,312 KB
最終ジャッジ日時 2024-10-12 15:45:14
合計ジャッジ時間 4,711 ms
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 42
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

from collections import defaultdict, deque, Counter
# from functools import cache
# import copy
from itertools import combinations, permutations, product, accumulate, groupby, chain
# from more_itertools import distinct_permutations
from heapq import heapify, heappop, heappush
import math
import bisect
# from pprint import pprint
from random import randint, shuffle, randrange
# from sortedcontainers import SortedSet, SortedList, SortedDict
import sys
# sys.setrecursionlimit(2000000)
input = lambda: sys.stdin.readline().rstrip('\n')
inf = float('inf')
mod1 = 10**9+7
mod2 = 998244353
def ceil_div(x, y): return -(-x//y)
#################################################
N = int(input())
S = input()
dp = [0]*3
if S[0] == "L":
dp[0] = 1
elif S[0] == "R":
dp[1] = 1
elif S[0] == "U":
dp[2] = 1
else:
dp[0] = 1
dp[1] = 1
dp[2] = 1
for i in range(1, N):
s = S[i]
ndp = [0]*3
if s == "L":
ndp[0] = dp[0]+dp[2]
elif s == "R":
ndp[1] = dp[0]+dp[1]+dp[2]
elif s == "U":
ndp[2] = dp[0]+dp[1]+dp[2]
else:
ndp[0] = dp[0]+dp[2]
ndp[1] = dp[0]+dp[1]+dp[2]
ndp[2] = dp[0]+dp[1]+dp[2]
dp = ndp
dp[0] %= mod2
dp[1] %= mod2
dp[2] %= mod2
print(sum(dp)%mod2)
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