結果
| 問題 |
No.2929 Miracle Branch
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2024-10-12 15:54:33 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,491 bytes |
| コンパイル時間 | 250 ms |
| コンパイル使用メモリ | 81,844 KB |
| 実行使用メモリ | 77,696 KB |
| 最終ジャッジ日時 | 2024-10-12 15:54:44 |
| 合計ジャッジ時間 | 10,757 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 WA * 1 |
| other | AC * 8 WA * 35 |
ソースコード
# library from https://qiita.com/t_fuki/items/7cd50de54d3c5d063b4a
def gcd(a, b):
while a:
a, b = b%a, a
return b
def is_prime(n):
if n == 2:
return 1
if n == 1 or n%2 == 0:
return 0
m = n - 1
lsb = m & -m
s = lsb.bit_length()-1
d = m // lsb
test_numbers = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37]
for a in test_numbers:
if a == n:
continue
x = pow(a,d,n)
r = 0
if x == 1:
continue
while x != m:
x = pow(x,2,n)
r += 1
if x == 1 or r == s:
return 0
return 1
def find_prime_factor(n):
if n%2 == 0:
return 2
m = int(n**0.125)+1
for c in range(1,n):
f = lambda a: (pow(a,2,n)+c)%n
y = 0
g = q = r = 1
k = 0
while g == 1:
x = y
while k < 3*r//4:
y = f(y)
k += 1
while k < r and g == 1:
ys = y
for _ in range(min(m, r-k)):
y = f(y)
q = q*abs(x-y)%n
g = gcd(q,n)
k += m
k = r
r *= 2
if g == n:
g = 1
y = ys
while g == 1:
y = f(y)
g = gcd(abs(x-y),n)
if g == n:
continue
if is_prime(g):
return g
elif is_prime(n//g):
return n//g
else:
return find_prime_factor(g)
def factorize(n):
res = {}
while not is_prime(n) and n > 1: # nが合成数である間nの素因数の探索を繰り返す
p = find_prime_factor(n)
s = 0
while n%p == 0: # nが素因数pで割れる間割り続け、出力に追加
n //= p
s += 1
res[p] = s
if n > 1: # n>1であればnは素数なので出力に追加
res[n] = 1
return res
x = int(input())
if x == 1:
print(2)
print(1,2)
print("b","g")
exit()
fac = factorize(x)
gre = []
for key, val in fac.items():
if key == 2:
gre.extend([4] * (val//2) + [2] * (val % 2))
else:
gre.extend([key] * val)
bro = len(gre)
tot = bro + sum(gre)
if tot > 200000:
print(-1)
exit()
print(tot)
for i in range(1, bro):
print(i, i+1)
cnt = bro+1
for i in range(bro):
for j in range(gre[i]):
print(i+1, cnt)
cnt += 1