結果

問題 No.2929 Miracle Branch
コンテスト
ユーザー 👑 binap
提出日時 2024-10-12 15:59:12
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 4,421 bytes
コンパイル時間 4,215 ms
コンパイル使用メモリ 262,860 KB
最終ジャッジ日時 2025-02-24 18:19:06
ジャッジサーバーID
（参考情報） 		judge1 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 30 WA * 13
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;

template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}

template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}

// Sieve of Eratosthenes
// https://youtu.be/UTVg7wzMWQc?t=2774
struct Sieve {
  int n;
  vector<int> f, primes;
  Sieve(int n=1):n(n), f(n+1) {
    f[0] = f[1] = -1;
    for (long long i = 2; i <= n; ++i) {
      if (f[i]) continue;
      primes.push_back(i);
      f[i] = i;
      for (long long j = i*i; j <= n; j += i) {
        if (!f[j]) f[j] = i;
      }
    }
  }
  bool isPrime(int x) { return f[x] == x;}
  vector<int> factorList(int x) {
    vector<int> res;
    while (x != 1) {
      res.push_back(f[x]);
      x /= f[x];
    }
    return res;
  }
  vector<pair<ll,int>> factor(ll x) {
    vector<pair<ll,int>> res;
    for (int p : primes) {
      int y = 0;
      while (x%p == 0) x /= p, ++y;
      if (y != 0) res.emplace_back(p,y);
    }
    if (x != 1) res.emplace_back(x,1);
    return res;
  }
	int num_of_divisors(long long x){
		auto f = factor(x);
		long long res = 1;
		for(auto [p, val] : f){
			res *= val + 1;
		}
		return res;
	}
	set<long long> divisors(long long x){
		set<long long> se = {1};
		auto f = factor(x);
		for(auto [key, value] : f){
			set<long long> old = se;
			for(long long y : old){
				rep(i, value + 1){
					se.insert(y);
					y *= key;
				}
			}
		}
		return se;
	}
};

const int M = 200000;

int main(){
	long long x;
	cin >> x;
	if(x == 1){
		cout << "2\n";
		cout << "1 2\n";
		cout << "b g\n";
		return 0;
	}
	Sieve sieve(M);
	vector<long long> vec;
	auto f = sieve.factor(x);
	long long tot = 0;
	for(auto [prime, cnt] : f){
		if(prime == 2 and cnt >= 2){
			vec.emplace_back(4);
			tot += 5;
			cnt -= 2;
		}
		rep(_, cnt){
			vec.emplace_back(prime);
			tot += prime + 1;
		}
	}
	if(tot > M){
		cout << "-1\n";
		return 0;
	}
	cout << tot << "\n";
	vector<pair<int, int>> G;
	int idx1 = 0;
	int idx2 = 0;
	for(long long val : vec){
		idx2 += val;
	}
	vector<char> color(tot);
	for(long long val : vec){
		rep(_, val){
			G.emplace_back(idx1, idx2);
			color[idx1] = 'g';
			idx1++;
		}
		color[idx2] = 'b';
		idx2++;
	}
	while(idx1 < idx2 - 1){
		G.emplace_back(idx1, idx1 + 1);
		idx1++;
	}
	for(auto [u, v] : G){
		cout << u + 1 << ' ' << v + 1 << "\n";
	}
	cout << color;
	return 0;
}
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