結果

問題 No.2928 Gridpath
ユーザー prin_kemkem
提出日時 2024-10-12 16:21:41
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 145 ms / 2,000 ms
コード長 1,572 bytes
コンパイル時間 184 ms
コンパイル使用メモリ 82,100 KB
実行使用メモリ 78,508 KB
最終ジャッジ日時 2024-10-12 16:21:44
合計ジャッジ時間 2,559 ms
ジャッジサーバーID
(参考情報)
judge3 / judge
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 20
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

from collections import defaultdict, deque, Counter
# from functools import cache
# import copy
from itertools import combinations, permutations, product, accumulate, groupby, chain
# from more_itertools import distinct_permutations
from heapq import heapify, heappop, heappush
import math
import bisect
# from pprint import pprint
from random import randint, shuffle, randrange
# from sortedcontainers import SortedSet, SortedList, SortedDict
import sys
# sys.setrecursionlimit(2000000)
input = lambda: sys.stdin.readline().rstrip('\n')
inf = float('inf')
mod1 = 10**9+7
mod2 = 998244353
def ceil_div(x, y): return -(-x//y)
#################################################
def ok(ni, nj, i, j):
if not (0 <= ni < H and 0 <= nj < W) or been[ni][nj]: return False
for di, dj in D:
if not (0 <= ni+di < H and 0 <= nj+dj < W): continue
if ni+di == i and nj+dj == j: continue
if been[ni+di][nj+dj]: return False
return True
H, W = map(int, input().split())
si, sj = map(lambda x: int(x)-1, input().split())
ti, tj = map(lambda x: int(x)-1, input().split())
D = [(0, 1), (0, -1), (1, 0), (-1, 0)]
been = [[False]*W for _ in range(H)]
stack = [(si, sj)]
ans = 0
while stack:
i, j = stack.pop()
if i >= 0:
if i == ti and j == tj:
ans += 1
continue
been[i][j] = True
stack.append((~i, j))
for di, dj in D:
ni, nj = i+di, j+dj
if ok(ni, nj, i, j):
stack.append((ni, nj))
else:
i = ~i
been[i][j] = False
print(ans)
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