結果

問題 No.2929 Miracle Branch
ユーザー igeeeigeee
提出日時 2024-10-12 16:36:09
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 5,277 bytes
コンパイル時間 4,688 ms
コンパイル使用メモリ 267,880 KB
実行使用メモリ 22,144 KB
最終ジャッジ日時 2024-10-12 16:36:32
合計ジャッジ時間 17,246 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 50 ms
21,960 KB
testcase_01 WA -
testcase_02 AC 50 ms
22,028 KB
testcase_03 WA -
testcase_04 WA -
testcase_05 WA -
testcase_06 WA -
testcase_07 WA -
testcase_08 WA -
testcase_09 WA -
testcase_10 WA -
testcase_11 WA -
testcase_12 WA -
testcase_13 WA -
testcase_14 WA -
testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 WA -
testcase_19 WA -
testcase_20 WA -
testcase_21 WA -
testcase_22 WA -
testcase_23 WA -
testcase_24 WA -
testcase_25 WA -
testcase_26 WA -
testcase_27 WA -
testcase_28 AC 51 ms
22,016 KB
testcase_29 AC 51 ms
21,984 KB
testcase_30 AC 52 ms
21,968 KB
testcase_31 AC 50 ms
22,052 KB
testcase_32 AC 51 ms
21,992 KB
testcase_33 AC 50 ms
22,016 KB
testcase_34 WA -
testcase_35 WA -
testcase_36 AC 53 ms
22,016 KB
testcase_37 WA -
testcase_38 WA -
testcase_39 WA -
testcase_40 WA -
testcase_41 WA -
testcase_42 WA -
testcase_43 AC 323 ms
22,016 KB
testcase_44 WA -
testcase_45 AC 51 ms
22,016 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
#define rep(i, n) for (long long i = 0; i < (long long)(n); i++)
#define rrep(i,start,end) for (long long i = start;i >= (long long)(end);i--)
#define repn(i,end) for(long long i = 0; i <= (long long)(end); i++)
#define reps(i,start,end) for(long long i = start; i < (long long)(end); i++)
#define repsn(i,start,end) for(long long i = start; i <= (long long)(end); i++)
#define each(p,a) for(auto &p:a)
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef vector<long long> vll;
typedef vector<pair<long long ,long long>> vpll;
typedef vector<vector<long long>> vvll;
typedef set<ll> sll;
typedef map<long long , long long> mpll;
typedef pair<long long ,long long> pll;
typedef tuple<long long , long long , long long> tpl3;
#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)
#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)
#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)
#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)
#define all(a)  (a).begin(),(a).end()
#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );
#define sz(x) (int)x.size()
// << std::fixed << std::setprecision(10)
const ll INF = 1LL << 60;
const ld EPS = 1e-9;
 
inline ll lfloor(ll x,ll m){return (x - ((x % m+ m)%m))/m;}
inline ll positive_mod(ll a,ll m){return (a % m + m)%m;}
inline ll popcnt(ull a){ return __builtin_popcountll(a);}
//0indexed
inline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}
inline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}
template<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}
template<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}
template<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}
template<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?" ":"");}return os;}
template<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << "{" << p.first << "," << p.second << "}";return os;}
template<class... T>void input(T&... a){(cin >> ... >> a);}
void print(){cout << endl;}
template<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}
template<class T> void pspace(const T& a){ cout << a << ' ';}
void perr(){cerr << endl;}
template<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}
void yes(bool i = true){ return print(i?"yes":"no"); }
void Yes(bool i = true){ return print(i?"Yes":"No"); }
void YES(bool i = true){ return print(i?"YES":"NO"); }
template <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}
template <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}
template <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}
template <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}
//grid探索用
vector<ll> _ta = {0,0,1,-1,1,1,-1,-1};
vector<ll> _yo = {1,-1,0,0,1,-1,1,-1};
bool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}
  
ll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}
ll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} 
const ll MOD9 = 998244353LL;
const ll MOD10 = 1000000007LL;


 
int main(){
  ios::sync_with_stdio(false);cin.tie(nullptr);
  //前処理、約数列挙PまでO(PlogP) //昇順でない
   ll P = 2 * lpow(10,5) + 1;
  vector<vector<ll>> primeFact(P+1);
  vector<ll> Deleted(P+1,0);
  Deleted[1] = 1;
  repsn(i,2,P){
    if(Deleted[i] != 0) continue;
    for(int j = i;j <= P;j += i){
      if(Deleted[j] !=0)continue;
      Deleted[j] = i;//iで初めに割られたということ
    }
  }
  repsn(i,1,P){
    primeFact[i].push_back(i);
    ll now = i;
    while(Deleted[now] != now){
      now /= Deleted[now];
      primeFact[i].push_back(now);
    }
    if(i != 1){
      primeFact[i].push_back(1);
    }
  }
  vll so;
  repsn(i,2,P){
    if(primeFact[i].size() <= 2){
      so.push_back(i);
    }
  }

  LL(x);
  if(x == 1){
    cout << 2 << endl;
    cout << "1 2" << endl;
    cout  << "b g" << endl;
    return 0;
  }
  vll sm;
  each(p,so){
    while(x % p == 0){
      x /= p;
      sm.push_back(p);
    }
    if(p == 2){
      vll tmp;
      while(sm.size() >= 2 ){
        sm.pop_back();
        sm.pop_back();
        tmp.push_back(4);
      }
      rep(z,tmp.size()){
        sm.push_back(4);
      }
    }
  }
  if(x != 1){
    sm.push_back(x);
  }
  ll n = reduce(all(sm)) + (ll)sm.size();
  if(reduce(all(sm)) + (ll)sm.size() >  2 * lpow(10,5)){
    cout << -1 << endl;
    return 0;
  }
  ll tya = sm.size();
  ll cnt= 0;

  cout << n << endl;
  rep(i,tya){
    rep(j,sm[i]){
      cout << i+1 << " " << tya+1 + cnt << " "  << endl;
      cnt++;

    }
  }
  rep(i,tya){
    pspace('b');
  }
  rep(i,n-tya){
    pspace('g');
  }
  print();

}
0