結果

問題 No.2930 Larger Mex
ユーザー prin_kemkem
提出日時 2024-10-12 17:15:31
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 340 ms / 2,000 ms
コード長 3,718 bytes
コンパイル時間 679 ms
コンパイル使用メモリ 82,048 KB
実行使用メモリ 111,168 KB
最終ジャッジ日時 2024-10-12 17:15:48
合計ジャッジ時間 15,898 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 50
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

from collections import defaultdict, deque, Counter
# from functools import cache
# import copy
from itertools import combinations, permutations, product, accumulate, groupby, chain
# from more_itertools import distinct_permutations
from heapq import heapify, heappop, heappush
import math
import bisect
# from pprint import pprint
from random import randint, shuffle, randrange
# from sortedcontainers import SortedSet, SortedList, SortedDict
import sys
# sys.setrecursionlimit(2000000)
input = lambda: sys.stdin.readline().rstrip('\n')
inf = float('inf')
mod1 = 10**9+7
mod2 = 998244353
def ceil_div(x, y): return -(-x//y)
#################################################   
# https://github.com/shakayami/ACL-for-python/blob/master/segtree.py
class segtree():
    n=1
    size=1
    log=2
    d=[0]
    op=None
    e=10**15
    def __init__(self,V,OP,E):
        self.n=len(V)
        self.op=OP
        self.e=E
        self.log=(self.n-1).bit_length()
        self.size=1<<self.log
        self.d=[E for i in range(2*self.size)]
        for i in range(self.n):
            self.d[self.size+i]=V[i]
        for i in range(self.size-1,0,-1):
            self.update(i)
    def set(self,p,x):
        assert 0<=p and p<self.n
        p+=self.size
        self.d[p]=x
        for i in range(1,self.log+1):
            self.update(p>>i)
    def get(self,p):
        assert 0<=p and p<self.n
        return self.d[p+self.size]
    def prod(self,l,r):
        assert 0<=l and l<=r and r<=self.n
        sml=self.e
        smr=self.e
        l+=self.size
        r+=self.size
        while(l<r):
            if (l&1):
                sml=self.op(sml,self.d[l])
                l+=1
            if (r&1):
                smr=self.op(self.d[r-1],smr)
                r-=1
            l>>=1
            r>>=1
        return self.op(sml,smr)
    def all_prod(self):
        return self.d[1]
    def max_right(self,l,f):
        assert 0<=l and l<=self.n
        assert f(self.e)
        if l==self.n:
            return self.n
        l+=self.size
        sm=self.e
        while(1):
            while(l%2==0):
                l>>=1
            if not(f(self.op(sm,self.d[l]))):
                while(l<self.size):
                    l=2*l
                    if f(self.op(sm,self.d[l])):
                        sm=self.op(sm,self.d[l])
                        l+=1
                return l-self.size
            sm=self.op(sm,self.d[l])
            l+=1
            if (l&-l)==l:
                break
        return self.n
    def min_left(self,r,f):
        assert 0<=r and r<=self.n
        assert f(self.e)
        if r==0:
            return 0
        r+=self.size
        sm=self.e
        while(1):
            r-=1
            while(r>1 and (r%2)):
                r>>=1
            if not(f(self.op(self.d[r],sm))):
                while(r<self.size):
                    r=(2*r+1)
                    if f(self.op(self.d[r],sm)):
                        sm=self.op(self.d[r],sm)
                        r-=1
                return r+1-self.size
            sm=self.op(self.d[r],sm)
            if (r& -r)==r:
                break
        return 0
    def update(self,k):
        self.d[k]=self.op(self.d[2*k],self.d[2*k+1])
    def __str__(self):
        return str([self.get(i) for i in range(self.n)])
N, M = map(int, input().split())
A = list(map(int, input().split()))
if M == 0:
    for i in range(N, 0, -1):
        print(i)
    exit()
st = segtree([-1]*M, min, inf)
ans = [0]*(N+2)
for i, a in enumerate(A):
    if a < M:
        st.set(a, i)
    l = st.prod(0, M)
    if l == -1: continue
    ans[i+1-l] += 1
    ans[i+2] -= 1
for i in range(N+1):
    ans[i+1] += ans[i]
print(*ans[1:N+1], sep="\n")
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