結果
問題 | No.2930 Larger Mex |
ユーザー | 寝癖 |
提出日時 | 2024-10-12 18:10:08 |
言語 | C++23 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 6,747 bytes |
コンパイル時間 | 6,354 ms |
コンパイル使用メモリ | 323,212 KB |
実行使用メモリ | 16,896 KB |
最終ジャッジ日時 | 2024-10-12 18:10:25 |
合計ジャッジ時間 | 14,423 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
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testcase_00 | WA | - |
testcase_01 | WA | - |
testcase_02 | WA | - |
testcase_03 | WA | - |
testcase_04 | WA | - |
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testcase_50 | WA | - |
testcase_51 | WA | - |
testcase_52 | WA | - |
ソースコード
#include <bits/stdc++.h> #include <atcoder/all> namespace neguse {} using namespace std; using namespace atcoder; using namespace neguse; typedef long long ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; typedef vector<int> vi; typedef vector<ll> vll; typedef vector<ld> vld; typedef vector<vi> vvi; typedef vector<vll> vvll; typedef vector<string> vs; typedef vector<pii> vpii; typedef vector<pll> vpll; #define _overload3(_1, _2, _3, name, ...) name #define _rep(i, n) repi(i, 0, n) #define repi(i, a, b) for (int i = int(a); i < int(b); ++i) #define rep(...) _overload3(__VA_ARGS__, repi, _rep, )(__VA_ARGS__) #define _rrep(i, n) rrepi(i, n - 1, -1) #define rrepi(i, a, b) for (int i = int(a); i > int(b); --i) #define rrep(...) _overload3(__VA_ARGS__, rrepi, _rrep)(__VA_ARGS__) #define _each1(i, v) for (auto &i : v) #define _each2(i, j, v) for (auto &[i, j] : v) #define each(...) _overload3(__VA_ARGS__, _each2, _each1, )(__VA_ARGS__) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define SUM(x) accumulate(all(x), 0LL) #define MAX(x) *max_element(all(x)) #define MIN(x) *min_element(all(x)) #define ACC(x, acc) partial_sum(all(x), acc.begin()+1) #define SORT(x) sort(all(x)) #define RSORT(x) sort(rall(x)) #define REVERSE(x) reverse(all(x)) #define dump(x) cerr << #x << " = " << (x) << '\n' #define print(x) cout << (x) << '\n' #define yes(f) cout << ((f) ? "Yes" : "No") << '\n' #define ge(v, x) (int)(lower_bound(all(v), x) - v.begin()) #define gt(v, x) (int)(upper_bound(all(v), x) - v.begin()) #define le(v, x) (int)(upper_bound(all(v), x) - v.begin()) - 1 #define lt(v, x) (int)(lower_bound(all(v), x) - v.begin()) - 1 template <class T> bool chmax(T &a, const T &b) { return a < b ? a = b, 1 : 0; } template <class T> bool chmin(T &a, const T &b) { return a > b ? a = b, 1 : 0; } ostream &operator<<(ostream &os, const modint998244353 &a) { return os << a.val(); } ostream &operator<<(ostream &os, const modint1000000007 &a) { return os << a.val(); } istream &operator>>(istream &is, modint998244353 &a) { int64_t t; is >> t; a = t; return is; } istream &operator>>(istream &is, modint1000000007 &a) { int64_t t; is >> t; a = t; return is; } template <class S, class T> ostream &operator<<(ostream &os, const pair<S, T> &p) { return os << '(' << p.first << ", " << p.second << ')'; } template <class S, class T> istream &operator>>(istream &is, pair<S, T> &p) { return is >> p.first >> p.second; } template <class T> istream &operator>>(istream &is, vector<T> &v) { for (T &x : v) is >> x; return is; } template <class T> ostream &operator<<(ostream &os, const vector<T> &v) { for (const T &x : v) os << x << ' '; return os; } template <class T> ostream &operator<<(ostream &os, const vector<vector<T>> &v) { for (const vector<T> &x : v) os << x << '\n'; return os; } #include <set> #include <cassert> #include <iostream> namespace neguse { template<typename T> class range_set { public: range_set() { S.insert({-inf, -inf}); S.insert({inf, inf}); } std::set<std::pair<T, T>> &get_all() { return S; } void insert(T l, T r) { auto itl = std::prev(S.upper_bound({l, inf})); auto itr = std::prev(S.upper_bound({r, inf})); if (itl->first <= l && l <= itl->second) l = itl->first; else itl++; if (itr->first <= r && r <= itr->second) r = itr->second; itr++; while (itl != itr) { cnt -= itl->second - itl->first; itl = S.erase(itl); } S.insert({l, r}); cnt += r - l; } void insert(T x) { insert(x, x+1); } void erase(T l, T r) { auto itl = std::prev(S.upper_bound({l, inf})); auto itr = std::prev(S.upper_bound({r, inf})); if (itl->first <= l && l < itl->second) { if (l != itl->first) { S.insert({itl->first, l}); cnt += l - itl->first; } } else itl++; if (itr->first < r && r < itr->second) { S.insert({r, itr->second}); cnt += itr->second - r; } if (r != itr->first) itr++; while (itl != itr) { cnt -= itl->second - itl->first; itl = S.erase(itl); } } void erase(T x) { erase(x, x+1); } bool contains(T l, T r) { auto it = std::prev(S.upper_bound({l, inf})); return it->first <= l && r <= it->second; } bool contains(T x) { return contains(x, x+1); } T count() { return cnt; } T size() { return S.size() - 2; } std::pair<T, T> get(T x) { auto it = S.upper_bound({x, inf}); it--; if (it->first <= x && x < it->second) return *it; return {-inf, -inf}; } range_set<T> intersect(T l, T r) { range_set<T> res; auto itl = std::prev(S.upper_bound({l, inf})); auto itr = std::prev(S.upper_bound({r, inf})); if (l < itl->second) res.insert(std::max(l, itl->first), std::min(r, itl->second)); while (itl++ != itr) res.insert(std::max(l, itl->first), std::min(r, itl->second)); if (itr->first < r) res.insert(std::max(l, itr->first), std::min(r, itr->second)); return res; } T mex(T x = 0) { auto [l, r] = get(x); if (l <= x && x < r) return r; return x; } void debug() { for (auto [l, r] : S) { if (l == inf || l == -inf) continue; std::cout << "[" << l << ", " << r << ")" << " "; } std::cout << '\n'; } private: std::set<std::pair<T, T>> S; T cnt = 0, inf = std::numeric_limits<T>::max() / 2; }; } int main() { int N, M; cin >> N >> M; vi A(N); cin >> A; if (M == 0) { rep(i, N) cout << N+1-A[i] << " \n"[i==N-1]; return 0; } range_set<int> rs; map<int, int> mp; deque<pii> dq; vector<ll> ans(N+2); rep(r, N) { dq.emplace_back(r, A[r]); if (mp[A[r]]++ == 0) rs.insert(A[r]); while (rs.mex() >= M) { auto [l, x] = dq.front(); dq.pop_front(); if (--mp[x] == 0) rs.erase(x); } if (!dq.empty()) { int l = dq.front().first; ans[1]++; ans[r-l+2]--; } } rep(i, N+1) ans[i+1] += ans[i]; rep(i, 1, N+1) ans[i] = N+1-i-ans[i]; rep(i, 1, N+1) cout << ans[i] << " \n"[i==N]; return 0; }