結果
問題 | No.2935 Division Into 3 (Mex Edition) |
ユーザー |
👑 ![]() |
提出日時 | 2024-10-14 09:21:50 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 412 ms / 5,000 ms |
コード長 | 2,548 bytes |
コンパイル時間 | 2,316 ms |
コンパイル使用メモリ | 207,168 KB |
最終ジャッジ日時 | 2025-02-24 19:24:45 |
ジャッジサーバーID (参考情報) |
judge4 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 21 |
ソースコード
#include <bits/stdc++.h> using namespace std; using ll=long long; const int INF=2100000000; #define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++) template<class T> bool chmin(T &a,T b){if(a>b){a=b;return 1;}else return 0;} int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int N; cin >> N; vector<int> A(N), C(N); rep(i, 0, N) cin >> A[i]; const int D = 3; const int M = 100'001; vector<vector<int>> G(M); vector<int> ind(M, 3); rep(i, 0, M) rep(j, 0, D) G[i].push_back(-1); rep(i, 0, N){ G[A[i]].push_back(i); } rep(i, 0, M) rep(j, 0, D) G[i].push_back(N); const int B = 2048; vector<int> div_val(N + 1); vector<int> div_left(B + 1, INF); rep(i, 0, N + 1){ div_val[i] = (i * B) / N; chmin(div_left[div_val[i]], i); } for (int i = B; i > 0; i--) chmin(div_left[i - 1], div_left[i]); vector pre(D, vector(B + 1, vector<int>(B + 1, INF))); vector val(D, vector<int>(B + 1, INF)); rep(i, 0, D) rep(j, 0, M){ chmin(val[i][div_val[G[j][3 + i]]], j); } int div_ind = 0; rep(i, 0, N + 1){ while (div_ind != B + 1 && div_left[div_ind] == i){ rep(j, 0, 3){ pre[j][div_ind] = val[j]; for (int k = B; k > 0; k--){ chmin(pre[j][div_ind][k - 1], pre[j][div_ind][k]); } } div_ind++; } if (i == N) break; C[i] = ind[A[i]]; ind[A[i]]++; rep(j, 0, D){ chmin(val[j][div_val[G[A[i]][ind[A[i]] + j]]], A[i]); } } int Q; cin >> Q; ll F = 0; rep(rp, 0, Q){ ll l, r; cin >> l >> r; l ^= F, r ^= F; l--; vector<int> ans(3); rep(i, 0, 3){ ans[i] = pre[i][div_val[l]][div_val[r - 1] + 1]; } int L = div_left[div_val[l]]; int R = div_left[div_val[r - 1] + 1]; while (L < l){ rep(j, 0, D){ if (G[A[L]][C[L] + j + 1] >= R){ chmin(ans[j], A[L]); } } L++; } while (r < R){ R--; rep(j, 0, D){ if (G[A[R]][C[R] - j - 1] < L){ chmin(ans[j], A[R]); } } } F = 0; int tmp = 0; rep(i, 0, 3){ F += ans[i]; if (ans[i] == 0) tmp++; } chmin(F, r - l - tmp); cout << F << "\n"; } }