結果

問題 No.389 ロジックパズルの組み合わせ
ユーザー paruki
提出日時 2016-07-08 22:35:10
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 162 ms / 2,000 ms
コード長 2,914 bytes
コンパイル時間 1,648 ms
コンパイル使用メモリ 169,348 KB
実行使用メモリ 5,580 KB
最終ジャッジ日時 2024-10-13 04:35:50
合計ジャッジ時間 5,999 ms
ジャッジサーバーID
(参考情報)
judge2 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 99
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ソースコード

diff #
プレゼンテーションモードにする

#include "bits/stdc++.h"
using namespace std;
#define FOR(i,j,k) for(int (i)=(j);(i)<(int)(k);++(i))
#define rep(i,j) FOR(i,0,j)
#define each(x,y) for(auto &(x):(y))
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define debug(x) cout<<#x<<": "<<(x)<<endl
#define smax(x,y) (x)=max((x),(y))
#define smin(x,y) (x)=min((x),(y))
#define MEM(x,y) memset((x),(y),sizeof (x))
#define sz(x) (int)(x).size()
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<ll> vll;
template<int MOD>
class ModInt{
public:
ModInt():value(0){}
ModInt(int val):value(val<0?MOD+val%MOD:val%MOD){ }
ModInt& operator+=(ModInt that){
value = value+that.value;
if(value>=MOD)value-=MOD;
return *this;
}
ModInt& operator-=(ModInt that){
value -= that.value;
if(value<0)value+=MOD;
return *this;
}
ModInt& operator*=(ModInt that){
value = (int)((long long)value * that.value % MOD);
return *this;
}
ModInt &operator/=(ModInt that){
return *this *= that.inverse();
}
ModInt operator+(ModInt that) const{
return ModInt(*this)+=that;
}
ModInt operator-(ModInt that) const{
return ModInt(*this)-=that;
}
ModInt operator*(ModInt that) const{
return ModInt(*this)*=that;
}
ModInt operator/(ModInt that) const {
return ModInt(*this) /= that;
}
ModInt operator^(long long k) const{
ModInt n = *this, res = 1;
while(k){
if(k & 1)res *= n;
n *= n;
k >>= 1;
}
return res;
}
ModInt inverse() const {
long long a = value, b = MOD, u = 1, v = 0;
while(b) {
long long t = a / b;
a -= t * b;
swap(a, b);
u -= t * v;
swap(u, v);
}
return ModInt(u);
}
int toi() const{ return value; }
private:
int value;
};
typedef ModInt<1000000007> mint;
ostream& operator<<(ostream& os, const mint& x){
os << x.toi();
return os;
}
/*
nr
O(n+r)
*/
mint nCr(int n, int r){
mint res = 1;
for(int i = 2; i <= n; ++i)
res *= i;
for(int i = 2; i <= n - r; ++i)
res /= i;
for(int i = 2; i <= r; ++i)
res /= i;
return res;
}
/*
nr
O(n+r)
*/
mint nHr(int n, int r){
return nCr(n + r - 1, r);
}
int main(){
int N;
cin >> N;
vi a;
int x;
while(~scanf("%d", &x)){
a.push_back(x);
}
if(sz(a) == 1 && (a[0] == 0 || a[0] == N)){
puts("1");
return 0;
}
int sum = -1;
each(y, a){
sum += y + 1;
if(sum > N){
puts("NA");
return 0;
}
}
mint ans = nHr(sz(a) + 1, N - sum);
cout << ans << endl;
}
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