結果
問題 | No.227 簡単ポーカー |
ユーザー |
|
提出日時 | 2024-10-22 00:47:57 |
言語 | Python3 (3.13.1 + numpy 2.2.1 + scipy 1.14.1) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,773 bytes |
コンパイル時間 | 311 ms |
コンパイル使用メモリ | 12,800 KB |
実行使用メモリ | 11,008 KB |
最終ジャッジ日時 | 2024-10-22 00:47:58 |
合計ジャッジ時間 | 1,408 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
other | AC * 11 WA * 3 |
ソースコード
def main(): a_lst = list(map(int, input().split(' '))) if judge_full_house(a_lst): print('FULL HOUSE') elif judge_3_card(a_lst): print('THREE CARD') elif judge_2_pair(a_lst): print('TWO PAIR') elif judge_1_pair(a_lst): print('ONE PAIR') else: print('NO HAND') def judge_full_house(lst): card_dict = {} for ele in lst: if ele not in card_dict.keys(): card_dict[ele] = 1 else: card_dict[ele] += 1 isExist3 = False isExist2 = False for val in card_dict.values(): if not isExist3 and val == 3: isExist3 = True elif not isExist2 and val == 2: isExist2 = True if isExist2 and isExist3: return True else: return False def judge_3_card(lst): card_dict = {} for ele in lst: if ele not in card_dict.keys(): card_dict[ele] = 1 else: card_dict[ele] += 1 if card_dict[ele] == 3: return True return False def judge_2_pair(lst): card_dict = {} for ele in lst: if ele not in card_dict.keys(): card_dict[ele] = 1 else: card_dict[ele] += 1 isFirst2 = False for val in card_dict.values(): if val == 2 and not isFirst2: isFirst2 = True elif val == 2 and isFirst2: return True return False def judge_1_pair(lst): card_dict = {} for ele in lst: if ele not in card_dict.keys(): card_dict[ele] = 1 else: card_dict[ele] += 1 for val in card_dict.values(): if val == 2: return True return False if __name__ == '__main__': main()