結果
問題 |
No.389 ロジックパズルの組み合わせ
|
ユーザー |
👑 ![]() |
提出日時 | 2016-07-08 23:41:30 |
言語 | C90 (gcc 12.3.0) |
結果 |
AC
|
実行時間 | 52 ms / 2,000 ms |
コード長 | 213 bytes |
コンパイル時間 | 361 ms |
コンパイル使用メモリ | 20,608 KB |
実行使用メモリ | 9,580 KB |
最終ジャッジ日時 | 2024-10-13 07:27:09 |
合計ジャッジ時間 | 4,242 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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ファイルパターン | 結果 |
---|---|
other | AC * 99 |
コンパイルメッセージ
main.c:2:17: warning: data definition has no type or storage class 2 | long v[1<<20],s;n,k,i,t; | ^ main.c:2:17: warning: type defaults to ‘int’ in declaration of ‘n’ [-Wimplicit-int] main.c:2:19: warning: type defaults to ‘int’ in declaration of ‘k’ [-Wimplicit-int] 2 | long v[1<<20],s;n,k,i,t; | ^ main.c:2:21: warning: type defaults to ‘int’ in declaration of ‘i’ [-Wimplicit-int] 2 | long v[1<<20],s;n,k,i,t; | ^ main.c:2:23: warning: type defaults to ‘int’ in declaration of ‘t’ [-Wimplicit-int] 2 | long v[1<<20],s;n,k,i,t; | ^ main.c:3:1: warning: return type defaults to ‘int’ [-Wimplicit-int] 3 | main(j){ | ^~~~ main.c: In function ‘main’: main.c:3:1: warning: type of ‘j’ defaults to ‘int’ [-Wimplicit-int] main.c:4:20: warning: implicit declaration of function ‘scanf’ [-Wimplicit-function-declaration] 4 | for(v[1]=s=scanf("%d",&n);j++<1e6;v[j]=v[P%j]*(P-P/j)%P); | ^~~~~ main.c:1:1: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’ +++ |+#include <stdio.h> 1 | #define P 1000000007 main.c:4:20: warning: incompatible implicit declaration of built-in function ‘scanf’ [-Wbuiltin-declaration-mismatch] 4 | for(v[1]=s=scanf("%d",&n);j++<1e6;v[j]=v[P%j]*(P-P/j)%P); | ^~~~~ main.c:4:20: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’ main.c:5:15: warning: incompatible implicit declaration of built-in function ‘scanf’ [-Wbuiltin-declaration-mismatch] 5 | for(;~scanf("%d",&t);k+=!!t)n-=t; | ^~~~~ main.c:5:15: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’ main.c:7:12: warning: implicit declaration of function ‘printf’ [-Wimplicit-function-declaration] 7 | s=!printf(s?"%ld":"NA",s); | ^~
ソースコード
#define P 1000000007 long v[1<<20],s;n,k,i,t; main(j){ for(v[1]=s=scanf("%d",&n);j++<1e6;v[j]=v[P%j]*(P-P/j)%P); for(;~scanf("%d",&t);k+=!!t)n-=t; for(;k/++i;)s=s*(n-i+2)%P*v[i]%P; s=!printf(s?"%ld":"NA",s); }