結果

問題 No.2957 Combo Deck Builder
ユーザー hirayuu_yc
提出日時 2024-11-08 22:42:22
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 302 ms / 1,000 ms
コード長 3,127 bytes
コンパイル時間 6,900 ms
コンパイル使用メモリ 336,396 KB
実行使用メモリ 25,708 KB
最終ジャッジ日時 2024-11-08 22:42:43
合計ジャッジ時間 16,070 ms
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 38
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

//https://atcoder.jp/contests/aising2020/submissions/59445625
#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return
    os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : "");
    return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return
    true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder
    ::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n -
    1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
int solve(){
int n;
cin >> n;
vector<vector<long long>> x_great(n + 1);
vector<vector<long long>> y_great(n + 1);
long long ans = 0;
rep(i, n){
int k, x, y;
cin >> k >> y >> x;
int c = n - k;
int guarantee = min(x, y);
ans += guarantee;
x -= guarantee;
y -= guarantee;
if(x > 0){
x_great[c].push_back(x);
}
if(y > 0){
y_great[n - c].push_back(y);
}
}
auto solve = [&](vector<vector<long long>> schedule){
long long res = 0;
priority_queue<long long> pq;
rep(i, n){
for(long long val : schedule[i]) pq.push(val);
if(pq.size()){
long long val = pq.top(); pq.pop();
res += val;
}
}
return res;
};
ans += solve(x_great);
ans += solve(y_great);
cout << ans << "\n";
return 0;
}
int main(){
solve();
return 0;
}
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