結果
| 問題 |
No.2959 Dolls' Tea Party
|
| コンテスト | |
| ユーザー |
sasa8uyauya
|
| 提出日時 | 2024-11-08 22:58:11 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 2,291 bytes |
| コンパイル時間 | 397 ms |
| コンパイル使用メモリ | 82,764 KB |
| 実行使用メモリ | 119,340 KB |
| 最終ジャッジ日時 | 2024-11-08 22:58:18 |
| 合計ジャッジ時間 | 6,738 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 5 TLE * 1 -- * 27 |
ソースコード
mod = 998244353
R = 3
Rinv = 332748118
W = [pow(R, (mod-1)>>i, mod) for i in range(24)]
Winv = [pow(Rinv, (mod-1)>>i, mod) for i in range(24)]
def fft(k, f):
for l in range(k, 0, -1):
d = 1<<l-1
U = [1]
for i in range(d):
U.append(U[-1]*W[l]%mod)
for i in range(1<<k-l):
for j in range(d):
s = i*2*d+j
f[s], f[s+d] = (f[s]+f[s+d])%mod, U[j]*(f[s]-f[s+d])%mod
def fftinv(k, f):
for l in range(1, k+1):
d = 1<<l-1
for i in range(1<<k-l):
u = 1
for j in range(i*2*d, (i*2+1)*d):
f[j+d] *= u
f[j], f[j+d] = (f[j]+f[j+d])%mod, (f[j]-f[j+d])%mod
u *= Winv[l]
u %= mod
def convolution(a, b):
le = len(a)+len(b)-1
k = le.bit_length()
n = 1<<k
a = a+[0]*(n-len(a))
b = b+[0]*(n-len(b))
fft(k, a)
fft(k, b)
for i in range(n):
a[i] *= b[i]
a[i] %= mod
fftinv(k, a)
ninv = pow(n, mod-2, mod)
for i in range(le):
a[i] *= ninv
a[i] %= mod
return a[:le]
def FPSinv(H):
I=[pow(H[0],M-2,M)]
l=1
while l<len(H):
I+=[0]*l
nI=convolution(H[:l*2],convolution(I,I)[:l*2])[:l*2]
for i in range(l*2):
nI[i]=(2*I[i]-nI[i])%M
I=nI
l*=2
return I[:len(H)]
def FPSlog(H):
H1=[H[i]*i%M for i in range(1,len(H))]+[0]
H2=FPSinv(H)
I=convolution(H1,H2)
I=[0]+[I[i]*fb[i+1]*fa[i]%M for i in range(len(H)-1)]
return I
def FPSexp(H):
I=[1]
l=1
while l<len(H):
I+=[0]*l
I2=FPSlog(I)[:l*2]
I3=H[:l*2]
I3[0]+=1
for i in range(l*2):
I3[i]-=I2[i]
nI=convolution(I,I3)[:l*2]
I=nI
l*=2
return I[:len(H)]
n,K=map(int,input().split())
a=[min(K,int(x)) for x in input().split()]
M=998244353
fa=[1,1]
fb=[1,1]
for i in range(2,10**4+1):
fa+=[fa[-1]*i%M]
fb+=[fb[-1]*(M//i)*fb[M%i]*fa[M%i-1]*(-1)%M]
fc=lambda n,k:fa[n]*fb[k]*fb[n-k]%M if n>=k>=0 else 0
g=[0]*(K+1)
for i in range(1,K+1):
if K%i==0:
c=[0]*(K+1)
for v in a:
c[v//(K//i)]+=1
l=1<<(len(bin(i+1))-2)
q=[0]*l
for j in range(1,K+1):
if c[j]>0:
q2=[1]+[fb[k] for k in range(1,j+1)]
q2=q2[:i+1]
q2+=[0]*(l-len(q2))
q2=FPSlog(q2)
for k in range(l):
q[k]+=q2[k]*c[j]
q[k]%=M
q=FPSexp(q)
g[i]=q[i]*fa[i]%M
ans=0
from math import gcd
for i in range(K):
ans+=g[gcd(i,K)]
ans%=M
print(ans*pow(K,M-2,M)%M)
sasa8uyauya