結果

問題 No.2966 Simple Plus Minus Problem
ユーザー KumaTachiRen
提出日時 2024-11-16 16:29:05
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
MLE  
実行時間 -
コード長 4,881 bytes
コンパイル時間 6,392 ms
コンパイル使用メモリ 320,656 KB
実行使用メモリ 818,012 KB
最終ジャッジ日時 2024-11-16 16:30:07
合計ジャッジ時間 42,300 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2 MLE * 1
other AC * 44 MLE * 10
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#include <atcoder/all>
using namespace atcoder;
using mint = modint998244353;
using vm = vector<mint>;
using vvm = vector<vm>;
inline ostream &operator<<(ostream &os, const mint x)
{
    return os << x.val();
};
inline istream &operator>>(istream &is, mint &x)
{
    long long v;
    is >> v;
    x = v;
    return is;
};
struct Fast
{
    Fast()
    {
        std::cin.tie(nullptr);
        ios::sync_with_stdio(false);
        cout << setprecision(10);
    }
} fast;
#define all(a) (a).begin(), (a).end()
#define contains(a, x) ((a).find(x) != (a).end())
#define rep(i, a, b) for (int i = (a); i < (int)(b); i++)
#define rrep(i, a, b) for (int i = (int)(b) - 1; i >= (a); i--)
#define YN(b) cout << ((b) ? "YES" : "NO") << "\n";
#define Yn(b) cout << ((b) ? "Yes" : "No") << "\n";
#define yn(b) cout << ((b) ? "yes" : "no") << "\n";
template <class T>
inline bool chmin(T &a, T b)
{
    if (a > b)
    {
        a = b;
        return true;
    }
    return false;
}
template <class T>
inline bool chmax(T &a, T b)
{
    if (a < b)
    {
        a = b;
        return true;
    }
    return false;
}
using ll = long long;
using vb = vector<bool>;
using vvb = vector<vb>;
using vi = vector<int>;
using vvi = vector<vi>;
using vl = vector<ll>;
using vvl = vector<vl>;
template <typename T1, typename T2>
ostream &operator<<(ostream &os, pair<T1, T2> &p)
{
    os << "(" << p.first << "," << p.second << ")";
    return os;
}
template <typename T>
ostream &operator<<(ostream &os, vector<T> &vec)
{
    for (int i = 0; i < (int)vec.size(); i++)
    {
        os << vec[i] << (i + 1 == (int)vec.size() ? "" : " ");
    }
    return os;
}
template <typename T>
istream &operator>>(istream &is, vector<T> &vec)
{
    for (int i = 0; i < (int)vec.size(); i++)
        is >> vec[i];
    return is;
}
ll floor(ll a, ll b) { return a >= 0 ? a / b : (a + 1) / b - 1; }
ll ceil(ll a, ll b) { return a > 0 ? (a - 1) / b + 1 : a / b; }
template <typename mint>
struct factorial
{
    vector<mint> f, g, h;
    factorial(int MAX = 0)
    {
        f.resize(1, mint{1});
        g.resize(1, mint{1});
        h.resize(1, mint{1});
        if (MAX > 0)
            extend(MAX + 1);
    }
    void extend(int m = -1)
    {
        int n = f.size();
        if (m == -1)
            m = n * 2;
        if (n >= m)
            return;
        f.resize(m);
        g.resize(m);
        h.resize(m);
        for (int i = n; i < m; i++)
            f[i] = f[i - 1] * mint(i);
        g[m - 1] = f[m - 1].inv();
        h[m - 1] = g[m - 1] * f[m - 2];
        for (int i = m - 2; i >= n; i--)
        {
            g[i] = g[i + 1] * mint(i + 1);
            h[i] = g[i] * f[i - 1];
        }
    }
    mint fact(int i)
    {
        if (i < 0)
            return mint(0);
        while (i >= (int)f.size())
            extend();
        return f[i];
    }
    mint fact_inv(int i)
    {
        if (i < 0)
            return mint(0);
        while (i >= (int)g.size())
            extend();
        return g[i];
    }
    mint inv(int i)
    {
        if (i < 0)
            return -inv(-i);
        while (i >= (int)h.size())
            extend();
        return h[i];
    }
    mint binom(int n, int r)
    {
        if (n < 0 || n < r || r < 0)
            return mint(0);
        return fact(n) * fact_inv(n - r) * fact_inv(r);
    }
    mint multinom(const vector<int> &r)
    {
        int n = 0;
        for (auto &x : r)
        {
            if (x < 0)
                return mint(0);
            n += x;
        }
        mint res = fact(n);
        for (auto &x : r)
            res *= fact_inv(x);
        return res;
    }
    mint binom_naive(int n, int r)
    {
        if (n < 0 || n < r || r < 0)
            return mint(0);
        mint ret = mint(1);
        r = min(r, n - r);
        for (int i = 1; i <= r; ++i)
            ret *= inv(i) * (n--);
        return ret;
    }
    mint P(int n, int r)
    {
        if (n < 0 || n < r || r < 0)
            return mint(0);
        return fact(n) * fact_inv(n - r);
    }
    mint H(int n, int r)
    {
        if (n < 0 || r < 0)
            return mint(0);
        return r == 0 ? 1 : binom(n + r - 1, r);
    }
};
void solve()
{
    int n, k;
    cin >> n >> k;
    vm a(n);
    cin >> a;
    factorial<mint> fact(1000000);
    if (k & 1) rep(i, 0, n) if (i & 1) a[i] = -a[i];
    vm g(n);
    {
        int m = (k + 1) / 2;
        if (m)
        {
            rep(i, 0, n) g[i] = fact.binom(m - 1 + i, i);
            a = convolution(a, g);
        }
    }
    {
        int m = k / 2;
        if (m)
        {
            rep(i, 0, n) g[i] = fact.binom(m - 1 + i, i) * (i & 1 ? -1 : 1);
            a = convolution(a, g);
        }
    }
    rep(i, 0, n) cout << a[i] << " \n"[i + 1 == n];
}
int main()
{
    int t = 1;
    // cin >> t;
    while (t--)
        solve();
}
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