結果

問題 No.2964 Obstruction Bingo
ユーザー 👑 binapbinap
提出日時 2024-11-16 17:40:48
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
TLE  
実行時間 -
コード長 3,371 bytes
コンパイル時間 4,890 ms
コンパイル使用メモリ 272,460 KB
実行使用メモリ 95,232 KB
最終ジャッジ日時 2024-11-16 17:44:33
合計ジャッジ時間 129,771 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge1
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
10,496 KB
testcase_01 AC 2 ms
54,912 KB
testcase_02 AC 60 ms
10,496 KB
testcase_03 AC 2 ms
57,216 KB
testcase_04 AC 3 ms
10,496 KB
testcase_05 AC 2,298 ms
87,596 KB
testcase_06 AC 2,244 ms
39,424 KB
testcase_07 AC 279 ms
17,444 KB
testcase_08 AC 2,352 ms
40,412 KB
testcase_09 AC 2,336 ms
87,240 KB
testcase_10 TLE -
testcase_11 AC 327 ms
63,376 KB
testcase_12 TLE -
testcase_13 AC 2,121 ms
85,636 KB
testcase_14 TLE -
testcase_15 AC 590 ms
68,252 KB
testcase_16 AC 564 ms
20,352 KB
testcase_17 AC 349 ms
64,000 KB
testcase_18 AC 1,309 ms
30,260 KB
testcase_19 AC 352 ms
63,640 KB
testcase_20 TLE -
testcase_21 AC 2,032 ms
83,360 KB
testcase_22 AC 160 ms
14,628 KB
testcase_23 AC 65 ms
10,624 KB
testcase_24 AC 137 ms
12,416 KB
testcase_25 TLE -
testcase_26 TLE -
testcase_27 TLE -
testcase_28 TLE -
testcase_29 TLE -
testcase_30 TLE -
testcase_31 TLE -
testcase_32 TLE -
testcase_33 TLE -
testcase_34 TLE -
testcase_35 TLE -
testcase_36 TLE -
testcase_37 TLE -
testcase_38 TLE -
testcase_39 TLE -
testcase_40 TLE -
testcase_41 TLE -
testcase_42 TLE -
testcase_43 TLE -
testcase_44 TLE -
testcase_45 TLE -
testcase_46 TLE -
testcase_47 TLE -
testcase_48 TLE -
testcase_49 TLE -
testcase_50 TLE -
testcase_51 TLE -
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;

template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}

template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}

using mint = modint998244353;

int main(){
	int l, k;
	cin >> l >> k;
	string s, t;
	cin >> s >> t;
	int n = (k + 1) * (k + 1);
	vector<int> a(26);
	cin >> a;
	int tot = 0;
	rep(i, 26) tot += a[i];
	vector<map<int, mint>> G(n);
	auto f = [&](int x, int y){
		return x * (k + 1) + y;
	};
	for(int x_from = 0; x_from < k + 1; x_from++){
		for(int y_from = 0; y_from < k + 1; y_from++){
			int from = f(x_from, y_from);
			rep(i, 26){
				int x_to = x_from;
				int y_to = y_from;
				if(s[x_from % l] == 'a' + i) x_to++;
				if(t[y_from % l] == 'a' + i) y_to++;
				int to = f(x_to, y_to);
				G[from][to] += mint(a[i]) / tot;
			}
		}
	}
	vector<mint> dp(n);
	dp[0] = 1;
	mint ans1 = 0;
	mint ans2 = 0;
	rep(_, k){
		vector<mint> dp_old(n);
		swap(dp, dp_old);
		rep(from, n){
			for(auto [to, c] : G[from]) dp[to] += dp_old[from] * c;
		}
		rep(to, n){
			int x_to = to / (k + 1);
			int y_to = to % (k + 1);
			if(x_to == y_to + l){
				ans1 += dp[to];
				dp[to] = 0;
			}
			if(x_to + l == y_to){
				ans2 += dp[to];
				dp[to] = 0;
			}
		}
	}
	cout << ans1 << ' ' << ans2 << "\n";
	return 0;
}
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