結果

問題 No.2964 Obstruction Bingo
ユーザー 👑 binapbinap
提出日時 2024-11-16 17:44:11
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
AC  
実行時間 1,718 ms / 2,468 ms
コード長 3,412 bytes
コンパイル時間 4,831 ms
コンパイル使用メモリ 272,396 KB
実行使用メモリ 52,276 KB
最終ジャッジ日時 2024-11-16 17:45:19
合計ジャッジ時間 60,457 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 49
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return
    os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : "");
    return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return
    true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder
    ::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n -
    1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
using mint = modint998244353;
int main(){
int l, k;
cin >> l >> k;
string s, t;
cin >> s >> t;
int n = (k + 1) * (k + 1);
vector<int> a(26);
cin >> a;
int tot = 0;
rep(i, 26) tot += a[i];
vector<map<int, mint>> G(n);
auto f = [&](int x, int y){
return x * (k + 1) + y;
};
for(int x_from = 0; x_from < k + 1; x_from++){
for(int y_from = 0; y_from < k + 1; y_from++){
int from = f(x_from, y_from);
rep(i, 26){
int x_to = x_from;
int y_to = y_from;
if(s[x_from % l] == 'a' + i) x_to++;
if(t[y_from % l] == 'a' + i) y_to++;
int to = f(x_to, y_to);
G[from][to] += mint(a[i]) / tot;
}
}
}
vector<mint> dp(n);
dp[0] = 1;
mint ans1 = 0;
mint ans2 = 0;
rep(_, k){
vector<mint> dp_old(n);
swap(dp, dp_old);
rep(from, n){
if(dp_old[from] == mint(0)) continue;
for(auto [to, c] : G[from]) dp[to] += dp_old[from] * c;
}
rep(to, n){
int x_to = to / (k + 1);
int y_to = to % (k + 1);
if(x_to == y_to + l){
ans1 += dp[to];
dp[to] = 0;
}
if(x_to + l == y_to){
ans2 += dp[to];
dp[to] = 0;
}
}
}
cout << ans1 << ' ' << ans2 << "\n";
return 0;
}
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