結果

問題 No.2967 Nana's Plus Permutation Game
ユーザー tassei903
提出日時 2024-11-16 23:14:38
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 794 ms / 2,000 ms
コード長 3,153 bytes
コンパイル時間 391 ms
コンパイル使用メモリ 82,048 KB
実行使用メモリ 95,072 KB
平均クエリ数 4170.09
最終ジャッジ日時 2024-11-16 23:15:17
合計ジャッジ時間 32,824 ms
ジャッジサーバーID
(参考情報)
judge2 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 65
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
input = lambda :sys.stdin.readline()[:-1]
ni = lambda :int(input())
na = lambda :list(map(int,input().split()))
yes = lambda :print("yes");Yes = lambda :print("Yes");YES = lambda : print("YES")
no = lambda :print("no");No = lambda :print("No");NO = lambda : print("NO")
#######################################################################
class scc_graph:
def __init__(self, N):
self.N = N
self.edges = []
self.start = [0] * (N + 1)
def csr(self):
for i in range(1, self.N + 1):
self.start[i] += self.start[i - 1]
counter = self.start[:]
self.elist = [0] * len(self.edges)
for a, b in self.edges:
self.elist[counter[a]] = b
counter[a] += 1
def add_edge(self, a, b):
self.edges.append((a, b))
self.start[a + 1] += 1
def scc(self):
self.csr()
N = self.N
now_ord = group_num = 0
visited = []
low = [0] * N
order = [-1] * N
ids = [0] * N
parent = [-1] * N
stack = []
groups = []
for i in range(N):
if order[i] == -1:
stack.append(i)
stack.append(i)
while stack:
v = stack.pop()
if order[v] == -1:
low[v] = order[v] = now_ord
now_ord += 1
visited.append(v)
for i in range(self.start[v], self.start[v + 1]):
to = self.elist[i]
if order[to] == -1:
stack.append(to)
stack.append(to)
parent[to] = v
else:
low[v] = min(low[v], order[to])
else:
if low[v] == order[v]:
group = []
while True:
u = visited.pop()
order[u] = N
ids[u] = group_num
group.append(u)
if u == v:
break
groups.append(group)
group_num += 1
if parent[v] != -1:
low[parent[v]] = min(low[parent[v]], low[v])
for i, x in enumerate(ids):
ids[i] = group_num - 1 - x
return group_num, ids, groups[::-1]
def ask(i, j):
print("1", i, j, flush=True)
return ni()
n = ni()
p = [-1] + [ask(i, i) for i in range(1, n + 1)]
scc = scc_graph(n + 1)
for i in range(1, n + 1):
if p[i] != -1:
scc.add_edge(p[i], i)
group_num, ids, groups = scc.scc()
dp = [0] * (n + 1)
for i in groups:
x = i[0]
if p[x] == -1:
continue
dp[x] = dp[p[x]] + 1
i = dp.index(max(dp))
ans = [-1] * (1 + n)
ans[i] = 1
now = i
for j in range(n - 1):
k = ask(now, i)
ans[k] = j + 2
now = k
print(2, *ans[1:])
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