結果

問題 No.2967 Nana's Plus Permutation Game
コンテスト
ユーザー tassei903
提出日時 2024-11-16 23:14:38
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 794 ms / 2,000 ms
コード長 3,153 bytes
コンパイル時間 391 ms
コンパイル使用メモリ 82,048 KB
実行使用メモリ 95,072 KB
平均クエリ数 4170.09
最終ジャッジ日時 2024-11-16 23:15:17
合計ジャッジ時間 32,824 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 65
権限があれば一括ダウンロードができます

ソースコード

diff # 

import sys
input = lambda :sys.stdin.readline()[:-1]
ni = lambda :int(input())
na = lambda :list(map(int,input().split()))
yes = lambda :print("yes");Yes = lambda :print("Yes");YES = lambda : print("YES")
no = lambda :print("no");No = lambda :print("No");NO = lambda : print("NO")
#######################################################################

class scc_graph:

    def __init__(self, N):
        self.N = N
        self.edges = []
        self.start = [0] * (N + 1)

    def csr(self):
        for i in range(1, self.N + 1):
            self.start[i] += self.start[i - 1]
        counter = self.start[:]
        self.elist = [0] * len(self.edges)
        for a, b in self.edges:
            self.elist[counter[a]] = b
            counter[a] += 1

    def add_edge(self, a, b):
        self.edges.append((a, b))
        self.start[a + 1] += 1

    def scc(self):
        self.csr()
        N = self.N
        now_ord = group_num = 0
        visited = []
        low = [0] * N
        order = [-1] * N
        ids = [0] * N
        parent = [-1] * N
        stack = []
        groups = []
        for i in range(N):
            if order[i] == -1:
                stack.append(i)
                stack.append(i)
                while stack:
                    v = stack.pop()
                    if order[v] == -1:
                        low[v] = order[v] = now_ord
                        now_ord += 1
                        visited.append(v)
                        for i in range(self.start[v], self.start[v + 1]):
                            to = self.elist[i]
                            if order[to] == -1:
                                stack.append(to)
                                stack.append(to)
                                parent[to] = v
                            else:
                                low[v] = min(low[v], order[to])
                    else:
                        if low[v] == order[v]:
                            group = []
                            while True:
                                u = visited.pop()
                                order[u] = N
                                ids[u] = group_num
                                group.append(u)
                                if u == v:
                                    break
                            groups.append(group)
                            group_num += 1
                        if parent[v] != -1:
                            low[parent[v]] = min(low[parent[v]], low[v])
        for i, x in enumerate(ids):
            ids[i] = group_num - 1 - x
        return group_num, ids, groups[::-1]

def ask(i, j):
    print("1", i, j, flush=True)
    return ni()

n = ni()

p = [-1] + [ask(i, i) for i in range(1, n + 1)]

scc = scc_graph(n + 1)
for i in range(1, n + 1):
    if p[i] != -1:
        scc.add_edge(p[i], i)

group_num, ids, groups = scc.scc()

dp = [0] * (n + 1)

for i in groups:
    x = i[0]
    if p[x] == -1:
        continue
    dp[x] = dp[p[x]] + 1
i = dp.index(max(dp))
ans = [-1] * (1 + n)
ans[i] = 1
now = i
for j in range(n - 1):
    k = ask(now, i)
    ans[k] = j + 2
    now = k

print(2, *ans[1:])
0