結果
| 問題 |
No.2955 Pizza Delivery Plan
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2024-11-24 19:24:33 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 273 ms / 2,000 ms |
| コード長 | 2,493 bytes |
| コンパイル時間 | 278 ms |
| コンパイル使用メモリ | 82,404 KB |
| 実行使用メモリ | 86,232 KB |
| 最終ジャッジ日時 | 2024-11-24 19:24:40 |
| 合計ジャッジ時間 | 7,057 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 28 |
ソースコード
## https://yukicoder.me/problems/no/2955
import math
def main():
N, K = map(int, input().split())
xy = []
for _ in range(N):
x, y = map(int, input().split())
xy.append((x, y))
# 原点からの距離を計算
dists_from_origins = []
for x, y in xy:
d = math.sqrt(x ** 2 + y ** 2)
dists_from_origins.append(d)
# 点i -> 点jのの移動距離の計算
matrix = [[-1] * N for _ in range(N)]
for i in range(N):
for j in range(N):
x1, y1 = xy[i]
x2, y2 = xy[j]
d = math.sqrt((x1 - x2) ** 2 + (y1 - y2) ** 2 )
matrix[i][j] = d
# popcountがK以下のbit(一度に宅配できる住宅の組み合わせ)ごとに最短でどれくらい帰ってくるかの計算を実施
base_bits = [[] for _ in range(K + 1)]
for bit in range(2 ** N):
popcount = 0
for i in range(N):
if bit & (1 << i) > 0:
popcount += 1
if popcount <= K:
base_bits[popcount].append(bit)
dp = {}
for i in range(N):
if (1 << i) not in dp:
dp[1 << i] = {}
dp[1 << i][i] = dists_from_origins[i]
for k in range(1, K):
b_bits = base_bits[k]
for bit in b_bits:
for j in range(N):
if bit & (1 << j) > 0:
continue
new_bit = bit | (1 << j)
for last, cost in dp[bit].items():
new_cost = cost + matrix[last][j]
if new_bit not in dp:
dp[new_bit] = {}
if j not in dp[new_bit]:
dp[new_bit][j] = float("inf")
dp[new_bit][j] = min(dp[new_bit][j], new_cost)
new_bit = {}
for bit, bit_map in dp.items():
base_cost = float("inf")
for key, cost in bit_map.items():
c = dists_from_origins[key] + cost
base_cost = min(base_cost, c)
new_bit[bit] = base_cost
# ---------
answer_dp = [float("inf")] * ( 2 ** N)
answer_dp[0] = 0.0
for bit in range(1, 2 ** N):
b = bit
while b > 0:
b_ = bit - b
if b in new_bit:
ans = new_bit[b] + answer_dp[b_]
answer_dp[bit] = min(answer_dp[bit], ans)
b = (b - 1) & bit
print(answer_dp[2 ** N - 1])
if __name__ == "__main__":
main()