結果
問題 | No.2979 直角三角形の個数 |
ユーザー |
![]() |
提出日時 | 2024-12-03 08:23:49 |
言語 | Rust (1.83.0 + proconio) |
結果 |
AC
|
実行時間 | 3,092 ms / 4,000 ms |
コード長 | 6,061 bytes |
コンパイル時間 | 13,888 ms |
コンパイル使用メモリ | 380,040 KB |
実行使用メモリ | 17,664 KB |
最終ジャッジ日時 | 2024-12-03 08:24:16 |
合計ジャッジ時間 | 23,435 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 26 |
コンパイルメッセージ
warning: unused variable: `ans` --> src/main.rs:81:13 | 81 | let mut ans = 0; | ^^^ help: if this is intentional, prefix it with an underscore: `_ans` | = note: `#[warn(unused_variables)]` on by default warning: variable does not need to be mutable --> src/main.rs:81:9 | 81 | let mut ans = 0; | ----^^^ | | | help: remove this `mut` | = note: `#[warn(unused_mut)]` on by default warning: function `test` is never used --> src/main.rs:77:4 | 77 | fn test() { | ^^^^ | = note: `#[warn(dead_code)]` on by default
ソースコード
// m^2-n^2, 2mn, m^2+n^2// m>n// m, nは互いに素かつ偶奇が違う// 2m(m+n)//// N/(2km(m+n))// の総和//// 1 <= n <= m-1 について商列挙っぽいことするとどうなる?// N=L の時Qとして// Q = N/(2m(m+n))// m+n= N/(2mQ)// n=N/(2mQ)-m// 4secならギリギリ間に合うか?fn main() {input!(n: usize);let sieve = Sieve::new(2000000);let mut p = vec![];let mut a = vec![];let mut ans = 0;for m in 2.. {if 2 * m * (m + 1) > n {break;}a.clear();let up = (m - 1).min(n / (2 * m) - m);let mut l = 1;while l <= up {let q = n / (2 * m * (m + l));let r = n / (2 * m * q) - m;a.push((l as u32 - 1, r.min(up) as u32, q));l = r + 1;}sieve.factorize(m, &mut p);if m % 2 == 0 {for (i, &f) in p.iter().enumerate() {let f = f as u32;let mut pre = 0;if i.count_ones() % 2 == 0 {for &(_, r, q) in a.iter().filter(|p| f <= p.1) {let u = r / f;ans += q * (u - pre) as usize;pre = u;}} else {for &(_, r, q) in a.iter().filter(|p| f <= p.1) {let u = r / f;ans -= q * (u - pre) as usize;pre = u;}}}} else {for (i, f) in p.iter().enumerate() {let f = *f as u32 * 2;let mut pre = 0;if i.count_ones() % 2 == 0 {for &(_, r, q) in a.iter().filter(|p| f <= p.1) {let u = r / f;ans += q * (u - pre) as usize;pre = u;}} else {for &(_, r, q) in a.iter().filter(|p| f <= p.1) {let u = r / f;ans -= q * (u - pre) as usize;pre = u;}}}}}println!("{ans}");}fn test() {let n = 10usize.pow(12);let sieve = Sieve::new(2000000);let mut p = vec![];let mut ans = 0;let mut sum = 0;for m in 2.. {if 2 * m * (m + 1) > n {break;}let mut l = 1;let mut c = 0;while l <= m - 1 {let q = n / (2 * m * (m + l));let r = n / (2 * m * q);l = r + 1;c += 1;}p.clear();sieve.factorize(m, &mut p);sum += c * p.len();/*if m % 2 == 0 {let up = (m - 1).min(n / (2 * m) - m);for (i, f) in p.iter().enumerate() {if i.count_ones() % 2 == 0 {ans += up / *f;} else {ans -= up / *f;}}} else {let up = (m - 1).min(n / (2 * m) - m) / 2;for (i, f) in p.iter().enumerate() {if i.count_ones() % 2 == 0 {ans += up / *f;} else {ans -= up / *f;}}}*/}println!("{}", sum);}// ---------- begin input macro ----------// reference: https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8#[macro_export]macro_rules! input {(source = $s:expr, $($r:tt)*) => {let mut iter = $s.split_whitespace();input_inner!{iter, $($r)*}};($($r:tt)*) => {let s = {use std::io::Read;let mut s = String::new();std::io::stdin().read_to_string(&mut s).unwrap();s};let mut iter = s.split_whitespace();input_inner!{iter, $($r)*}};}#[macro_export]macro_rules! input_inner {($iter:expr) => {};($iter:expr, ) => {};($iter:expr, $var:ident : $t:tt $($r:tt)*) => {let $var = read_value!($iter, $t);input_inner!{$iter $($r)*}};}#[macro_export]macro_rules! read_value {($iter:expr, ( $($t:tt),* )) => {( $(read_value!($iter, $t)),* )};($iter:expr, [ $t:tt ; $len:expr ]) => {(0..$len).map(|_| read_value!($iter, $t)).collect::<Vec<_>>()};($iter:expr, chars) => {read_value!($iter, String).chars().collect::<Vec<char>>()};($iter:expr, bytes) => {read_value!($iter, String).bytes().collect::<Vec<u8>>()};($iter:expr, usize1) => {read_value!($iter, usize) - 1};($iter:expr, $t:ty) => {$iter.next().unwrap().parse::<$t>().expect("Parse error")};}// ---------- end input macro ----------// --------- end sieve ----------pub struct Sieve {size: usize,factor: Vec<usize>,}impl Sieve {pub fn new(size: usize) -> Sieve {let mut factor = (0..(size + 1)).collect::<Vec<_>>();for i in (2..).take_while(|p| p * p <= size) {if i == factor[i] {for j in i..(size / i + 1) {factor[j * i] = i;}}}Sieve {size: size,factor: factor,}}pub fn factor(&self, n: usize) -> Option<usize> {assert!(n <= self.size);if n == 1 {None} else {Some(self.factor[n])}}pub fn factorize(&self, mut n: usize, res: &mut Vec<usize>) {assert!(n <= self.size);res.clear();res.push(1);while let Some(p) = self.factor(n) {let len = res.len();while n % p == 0 {n /= p;}for _ in 0..len {let v = res[res.len() - len] * p;res.push(v);}}}}// --------- end sieve ----------