結果
| 問題 |
No.2786 RMQ on Grid Path
|
| コンテスト | |
| ユーザー |
AngrySadEight
|
| 提出日時 | 2024-12-06 02:19:08 |
| 言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 1,722 ms / 6,000 ms |
| コード長 | 4,619 bytes |
| コンパイル時間 | 21,864 ms |
| コンパイル使用メモリ | 274,000 KB |
| 最終ジャッジ日時 | 2025-02-26 11:10:46 |
|
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 35 |
ソースコード
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <algorithm>
#include <atcoder/all>
#include <bitset>
#include <cassert>
#include <cmath>
#include <ctime>
#include <functional>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <random>
#include <set>
#include <stack>
#include <string>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
using namespace atcoder;
typedef long long ll;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repr(i, n) for (int i = (int)(n) - 1; i >= 0; i--)
#define repk(i, k, n) for (int i = k; i < (int)(n); i++)
#define all(v) v.begin(), v.end()
#define mod1 1000000007
#define mod2 998244353
#define mod3 100000007
#define vi vector<int>
#define vs vector<string>
#define vc vector<char>
#define vl vector<ll>
#define vb vector<bool>
#define vvi vector<vector<int>>
#define vvc vector<vector<char>>
#define vvl vector<vector<ll>>
#define vvb vector<vector<bool>>
#define vvvi vector<vector<vector<int>>>
#define vvvl vector<vector<vector<ll>>>
#define pii pair<int, int>
#define pil pair<int, ll>
#define pli pair<ll, int>
#define pll pair<ll, ll>
#define vpii vector<pair<int, int>>
#define vpll vector<pair<ll, ll>>
#define vvpii vector<vector<pair<int, int>>>
#define vvpll vector<vector<pair<ll, ll>>>
// using mint = modint998244353;
template <typename T>
void debug(T e) {
cerr << e << endl;
}
template <typename T>
void debug(vector<T> &v) {
rep(i, v.size()) { cerr << v[i] << " "; }
cerr << endl;
}
template <typename T>
void debug(vector<vector<T>> &v) {
rep(i, v.size()) {
rep(j, v[i].size()) { cerr << v[i][j] << " "; }
cerr << endl;
}
}
template <typename T>
void debug(vector<pair<T, T>> &v) {
rep(i, v.size()) { cerr << v[i].first << " " << v[i].second << endl; }
}
template <typename T>
void debug(set<T> &st) {
for (auto itr = st.begin(); itr != st.end(); itr++) {
cerr << *itr << " ";
}
cerr << endl;
}
template <typename T>
void debug(multiset<T> &ms) {
for (auto itr = ms.begin(); itr != ms.end(); itr++) {
cerr << *itr << " ";
}
cerr << endl;
}
template <typename T>
void debug(map<T, T> &mp) {
for (auto itr = mp.begin(); itr != mp.end(); itr++) {
cerr << itr->first << " " << itr->second << endl;
}
}
void debug_out() { cerr << endl; }
template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T) {
cerr << H << " ";
debug_out(T...);
}
int main() {
ll H, W;
cin >> H >> W;
vector<vector<ll>> A(H, vector<ll>(W));
for (ll i = 0; i < H; i++) {
for (ll j = 0; j < W; j++) {
cin >> A[i][j];
}
}
ll Q;
cin >> Q;
vector<ll> rs(Q);
vector<ll> cs(Q);
vector<ll> rt(Q);
vector<ll> ct(Q);
for (ll i = 0; i < Q; i++) {
cin >> rs[i] >> cs[i] >> rt[i] >> ct[i];
rs[i]--;
cs[i]--;
rt[i]--;
ct[i]--;
}
// 並列二分探索をしたい
vector<pll> p(0);
for (ll i = 0; i < H; i++) {
for (ll j = 0; j < W; j++) {
p.push_back(make_pair(A[i][j], i * W + j));
}
}
sort(all(p));
vector<ll> dx = {1, 0, -1, 0};
vector<ll> dy = {0, 1, 0, -1};
vector<ll> now_ng(Q, 0);
vector<ll> now_ok(Q, H * W);
for (ll i = 0; i < 20; i++) {
dsu tree(H * W);
vector<vector<ll>> mid_idx(H * W, vector<ll>(0));
for (ll j = 0; j < Q; j++) {
ll mid = (now_ng[j] + now_ok[j]) / 2;
mid_idx[mid].push_back(j);
}
for (ll j = 0; j < H * W; j++) {
for (ll k = 0; k < mid_idx[j].size(); k++) {
ll idx = mid_idx[j][k];
if (tree.same(rs[idx] * W + cs[idx], rt[idx] * W + ct[idx])) {
now_ok[idx] = j;
} else {
now_ng[idx] = j;
}
}
ll idx_x = p[j].second / W;
ll idx_y = p[j].second % W;
for (ll k = 0; k < 4; k++) {
if (idx_x + dx[k] >= 0 && idx_x + dx[k] < H &&
idx_y + dy[k] >= 0 && idx_y + dy[k] < W) {
if (A[idx_x][idx_y] >= A[idx_x + dx[k]][idx_y + dy[k]]) {
tree.merge(p[j].second,
(idx_x + dx[k]) * W + idx_y + dy[k]);
}
}
}
}
}
for (ll i = 0; i < Q; i++) {
cout << p[now_ok[i] - 1].first << endl;
}
}
AngrySadEight