結果
問題 | No.2984 [Cherry Anniversary 4] 満開の願いを込めた 27 の桜 |
ユーザー |
👑 |
提出日時 | 2024-12-09 11:53:56 |
言語 | D (dmd 2.109.1) |
結果 |
AC
|
実行時間 | 231 ms / 4,000 ms |
コード長 | 2,827 bytes |
コンパイル時間 | 3,171 ms |
コンパイル使用メモリ | 121,728 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-12-09 11:54:06 |
合計ジャッジ時間 | 8,090 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
other | AC * 22 |
ソースコード
import std.conv, std.functional, std.range, std.stdio, std.string;import std.algorithm, std.array, std.bigint, std.bitmanip, std.complex, std.container, std.math, std.mathspecial, std.numeric, std.regex, std.typecons;import core.bitop;class EOFException : Throwable { this() { super("EOF"); } }string[] tokens;string readToken() { for (; tokens.empty; ) { if (stdin.eof) { throw new EOFException; } tokens = readln.split; } auto token = tokens.front; tokens.popFront; return token; }int readInt() { return readToken.to!int; }long readLong() { return readToken.to!long; }string COLOR(string s = "") { return "\x1b[" ~ s ~ "m"; }bool chmin(T)(ref T t, in T f) { if (t > f) { t = f; return true; } else { return false; } }bool chmax(T)(ref T t, in T f) { if (t < f) { t = f; return true; } else { return false; } }int binarySearch(alias pred, T)(in T[] as) { int lo = -1, hi = cast(int)(as.length); for (; lo + 1 < hi; ) { const mid = (lo + hi) >> 1;(unaryFun!pred(as[mid]) ? hi : lo) = mid; } return hi; }int lowerBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a >= val)); }int upperBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a > val)); }void main() {try {for (; ; ) {const numCases = readInt;foreach (caseId; 0 .. numCases) {long[3][3][3] A;foreach (i; 0 .. 3) foreach (j; 0 .. 3) foreach (k; 0 .. 3) A[i][j][k] = readLong;long[3][3] X, Y, Z;foreach (j; 0 .. 3) foreach (k; 0 .. 3) X[j][k] = readLong;foreach (i; 0 .. 3) foreach (k; 0 .. 3) Y[i][k] = readLong;foreach (i; 0 .. 3) foreach (j; 0 .. 3) Z[i][j] = readLong;long[3][3] x, y, z;foreach (i; 0 .. 3) foreach (j; 0 .. 3) foreach (k; 0 .. 3) {x[j][k] += A[i][j][k];y[i][k] += A[i][j][k];z[i][j] += A[i][j][k];}int getCost(T)(T ps) {int cnt;foreach (i; 0 .. 3) if (ps[i] == i) ++cnt;return (cnt == 3) ? 0 : (cnt == 1) ? 1 : 2;}int ans = -1;foreach (ps; iota(3).permutations) foreach (qs; iota(3).permutations) foreach (rs; iota(3).permutations) {bool ok = true;foreach (j; 0 .. 3) foreach (k; 0 .. 3) ok = ok && (X[j][k] == x[qs[j]][rs[k]]);foreach (i; 0 .. 3) foreach (k; 0 .. 3) ok = ok && (Y[i][k] == y[ps[i]][rs[k]]);foreach (i; 0 .. 3) foreach (j; 0 .. 3) ok = ok && (Z[i][j] == z[ps[i]][qs[j]]);if (ok) {int cost;cost += getCost(ps);cost += getCost(qs);cost += getCost(rs);if (!~ans || ans > cost) ans = cost;debug writeln(ps, " ", qs, " ", rs, ": ", cost);}}writeln(ans);}}} catch (EOFException e) {}}