結果
問題 | No.2999 Long Long Friedrice |
ユーザー |
![]() |
提出日時 | 2024-12-16 10:33:02 |
言語 | Python3 (3.13.1 + numpy 2.2.1 + scipy 1.14.1) |
結果 |
WA
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 2,024 bytes |
コンパイル時間 | 238 ms |
コンパイル使用メモリ | 13,056 KB |
実行使用メモリ | 19,700 KB |
最終ジャッジ日時 | 2024-12-23 23:31:33 |
合計ジャッジ時間 | 18,286 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 6 |
other | AC * 32 WA * 1 |
ソースコード
import typingclass DSU:'''Implement (union by size) + (path halving)Reference:Zvi Galil and Giuseppe F. Italiano,Data structures and algorithms for disjoint set union problems'''def __init__(self, n: int = 0) -> None:self._n = nself.parent_or_size = [-1] * ndef merge(self, a: int, b: int) -> int:assert 0 <= a < self._nassert 0 <= b < self._nx = self.leader(a)y = self.leader(b)if x == y:return xif -self.parent_or_size[x] < -self.parent_or_size[y]:x, y = y, xself.parent_or_size[x] += self.parent_or_size[y]self.parent_or_size[y] = xreturn xdef same(self, a: int, b: int) -> bool:assert 0 <= a < self._nassert 0 <= b < self._nreturn self.leader(a) == self.leader(b)def leader(self, a: int) -> int:assert 0 <= a < self._nparent = self.parent_or_size[a]while parent >= 0:if self.parent_or_size[parent] < 0:return parentself.parent_or_size[a], a, parent = (self.parent_or_size[parent],self.parent_or_size[parent],self.parent_or_size[self.parent_or_size[parent]])return adef size(self, a: int) -> int:assert 0 <= a < self._nreturn -self.parent_or_size[self.leader(a)]def groups(self) -> typing.List[typing.List[int]]:leader_buf = [self.leader(i) for i in range(self._n)]result: typing.List[typing.List[int]] = [[] for _ in range(self._n)]for i in range(self._n):result[leader_buf[i]].append(i)return list(filter(lambda r: r, result))n = int(input())a = list(map(int, input().split()))b = list(map(int, input().split()))inf = 10**6d = DSU(inf + 1)for i in range(n):d.merge(a[i], a[i] + b[i])ans = 0for i in range(inf + 1):if d.same(1, i):ans = iprint(ans)