結果

問題 No.2992 Range ABCD String Query
ユーザー Kude
提出日時 2024-12-17 00:08:24
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 354 ms / 6,000 ms
コード長 3,235 bytes
コンパイル時間 3,652 ms
コンパイル使用メモリ 281,072 KB
実行使用メモリ 48,848 KB
最終ジャッジ日時 2024-12-17 00:08:40
合計ジャッジ時間 16,017 ms
ジャッジサーバーID
(参考情報)
judge2 / judge1
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ファイルパターン 結果
other AC * 41
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ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
namespace {
#pragma GCC diagnostic ignored "-Wunused-function"
#include<atcoder/all>
#pragma GCC diagnostic warning "-Wunused-function"
using namespace std;
using namespace atcoder;
#define rep(i,n) for(int i = 0; i < (int)(n); i++)
#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; i--)
#define all(x) begin(x), end(x)
#define rall(x) rbegin(x), rend(x)
template<class T> bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; } else return false; }
template<class T> bool chmin(T& a, const T& b) { if (b < a) { a = b; return true; } else return false; }
using ll = long long;
using P = pair<int,int>;
using VI = vector<int>;
using VVI = vector<VI>;
using VL = vector<ll>;
using VVL = vector<VL>;
template<class T, T (*add)(T, T), T (*zero)(), T (*mul)(T, T), T (*one)(), int N>
struct Mat : array<array<T, N>, N> {
using M = Mat<T, add, zero, mul, one, N>;
void make_identity() {
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
(*this)[i][j] = zero();
}
}
for (int i = 0; i < N; i++) {
(*this)[i][i] = one();
}
}
M& operator+=(const M& rhs) {
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
(*this)[i][j] = add((*this)[i][j], rhs[i][j]);
}
}
return *this;
}
M& operator*=(const M& rhs) {
static M temp;
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
temp[i][j] = zero();
}
}
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
for (int k = 0; k < N; k++) {
temp[i][k] = add(temp[i][k], mul((*this)[i][j], rhs[j][k]));
}
}
}
*this = temp;
return *this;
}
template <class I>
void inplace_pow(I k) {
assert(k >= 0);
static M temp;
temp = *this;
make_identity();
while (k) {
if (k & 1) *this *= temp;
k >>= 1;
if (k) temp *= temp;
}
}
friend ostream& operator<<(ostream& os, const M& A) {
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++) {
os << A[i][j] << " \n"[j + 1 == N];
}
}
return os;
}
};
constexpr int INF = 1001001001;
int add(int x, int y) { return min(x, y); }
int zero() { return INF; }
int mul(int x, int y) { return x + y; }
int one() { return 0; }
using M = Mat<int, add, zero, mul, one, 4>;
M e() {
M res;
res.make_identity();
return res;
}
M op(M a, M b) {
M c = a;
c *= b;
return c;
}
} int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int n, q;
cin >> n >> q;
string s;
cin >> s;
vector<M> init(n);
auto make_M = [&](char c) {
M a;
rep(i, 4) rep(j, 4) a[i][j] = INF;
int x = c - 'A';
rep(i, 4) rep(j, 4) if (i <= j) {
a[i][j] = !(i <= x && x <= j);
}
return a;
};
rep(i, n) {
init[i] = make_M(s[i]);
}
segtree<M, op, e> seg(init);
rep(_, q) {
int type;
cin >> type;
if (type == 1) {
int x;
char c;
cin >> x >> c;
x--;
s[x] = c;
seg.set(x, make_M(c));
} else {
int l, r;
cin >> l >> r;
l--;
auto a = seg.prod(l, r);
int res = INF;
rep(j, 4) chmin(res, a[0][j]);
cout << res << '\n';
}
}
}
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