結果

問題 No.1318 ABCD quadruplets
ユーザー LyricalMaestroLyricalMaestro
提出日時 2024-12-17 01:57:00
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 1,299 ms / 2,000 ms
コード長 3,264 bytes
コンパイル時間 345 ms
コンパイル使用メモリ 82,164 KB
実行使用メモリ 78,980 KB
最終ジャッジ日時 2024-12-17 01:57:14
合計ジャッジ時間 14,442 ms
ジャッジサーバーID
(参考情報)
judge1 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 30
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

## https://yukicoder.me/problems/no/1318
def calc(a, b, c, d):
return a * ( a + b + c + d) + b * (b + c + d) + c * (c + d) + d ** 2
def main():
N, M = map(int, input().split())
answer = [0] * (N + 1)
for a in range(M + 1):
n = 10 * a ** 2
if n > N:
break
answer[calc(a, a, a, a)] += 1
# 1
for a in range(M + 1):
if 2 * a ** 2 > 2 * N:
break
for b in range(a + 1, M + 1):
n = (a ** 2 + 3 * b ** 2) + (a + 3 * b) ** 2
if n > 2 * N:
break
answer[calc(a, b, b, b)] += 4
# 2
for a in range(M + 1):
if 6 * a ** 2 > 2 * N:
break
for b in range(a + 1, M + 1):
n = (2 * a ** 2 + 2 * b ** 2) + (2 * a + 2 * b) ** 2
if n > 2 * N:
break
answer[calc(a, a, b, b)] += 6
# 3
for a in range(M + 1):
if 12 * a ** 2 > 2 * N:
break
for b in range(a + 1, M + 1):
n = (3 * a ** 2 + b ** 2) + (3 * a + b) ** 2
if n > 2 * N:
break
answer[calc(a, a, a, b)] += 4
# 2
for a in range(M + 1):
if 6 * a ** 2 > N:
break
for b in range(a + 1, M + 1):
if (2 * a + b) ** 2 + 2 * a ** 2 + b ** 2 > 2 * N:
break
for c in range(b + 1, M + 1):
n = (2 * a + b + c) ** 2 + 2 * a ** 2 + b ** 2 + c ** 2
if n > 2 * N:
break
answer[calc(a, a, b, c)] += 12
# 2
for a in range(M + 1):
if 2 * a ** 2 > 2 * N:
break
for b in range(a + 1, M + 1):
if (a + 2 * b) ** 2 + a ** 2 + 2 * b ** 2 > 2 * N:
break
for c in range(b + 1, M + 1):
n = (a + 2 * b + c) ** 2 + a ** 2 + 2 * b ** 2 + c ** 2
if n > 2 * N:
break
answer[calc(a, b, b, c)] += 12
# 2
for a in range(M + 1):
if 2 * a ** 2 > 2 * N:
break
for b in range(a + 1, M + 1):
if (a + b) ** 2 + a ** 2 + b ** 2 > 2 * N:
break
for c in range(b + 1, M + 1):
n = (a + b + 2 * c) ** 2 + a ** 2 + b ** 2 + 2 * c ** 2
if n > 2 * N:
break
answer[calc(a, b, c, c)] += 12
for a in range(M + 1):
a2 = a ** 2
if 2 * a2 > 2 * N:
break
for b in range(a + 1, M + 1):
b2 = b ** 2
if a2 + b2 + (a + b) ** 2 > 2 * N:
break
for c in range(b + 1, M + 1):
c2 = c ** 2
if (a + b + c ) ** 2 + a2 + b2 + c2 > 2 * N:
break
for d in range(c + 1, M + 1):
d2 = d ** 2
if a2 + b2 + c2 + d2 + (a + b + c + d) ** 2 > 2 * N:
break
answer[calc(a, b, c, d)] += 24
for i in range(N + 1):
print(answer[i])
if __name__ == "__main__":
main()
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0