結果

問題 No.498 ワープクリスタル (給料日編)
ユーザー 37zigen
提出日時 2016-07-13 11:00:52
言語 Java
(openjdk 23)
結果
AC  
実行時間 687 ms / 2,000 ms
コード長 4,397 bytes
コンパイル時間 2,510 ms
コンパイル使用メモリ 78,888 KB
実行使用メモリ 175,860 KB
最終ジャッジ日時 2024-10-15 19:51:08
合計ジャッジ時間 12,955 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 21
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Arrays;
public class Main {
static void sample() {
System.out.println(1 + " " + 1 + " " + 5);
for (int i = 0; i < 5; i++) {
System.out.println(1 + " " + 1 + " " + 15);
}
}
static long MOD = 1_000_000_000 + 7;
static void solver() {
long gx = nl();
long gy = nl();
int k = ni();// the number of crystals
long[] x = new long[k];
long[] y = new long[k];
long[] n = new long[k];
for (int i = 0; i < k; i++) {
x[i] = nl();
y[i] = nl();
n[i] = ni();
}
memo = new long[16777233];
Arrays.fill(memo, -1);
long ans = dp(0, 0, x, y, n, gx, gy);
if (gx == 0 && gy == 0)
ans++;
out.println(ans);
}
static long[] memo;
static long dp(long curx, long cury, long[] x, long[] y, long[] n, long gx, long gy) {
int idx = 0;
for (int i = 0; i < n.length; i++) {
idx += pow(16, i) * n[i];
}
if (idx == 0)
return 0;
if (memo[idx] != -1) {
return memo[idx];
} else {
long sum = 0;
for (int i = 0; i < n.length; i++) {
if (n[i] > 0) {
long[] d = Arrays.copyOf(n, n.length);
d[i]--;
long nx = curx + x[i];
long ny = cury + y[i];
if (gx == nx && gy == ny) {
sum += 1;
}
sum += dp(nx, ny, x, y, d, gx, gy);
sum %= MOD;
}
}
memo[idx] = sum % MOD;
return sum;
}
}
static InputStream is;
static PrintWriter out;
static String INPUT = "";
public static void main(String[] args) throws Exception {
is = INPUT.isEmpty() ? System.in : new ByteArrayInputStream(INPUT.getBytes());
out = new PrintWriter(System.out);
solver();
out.flush();
}
static long nl() {
try {
long num = 0;
boolean minus = false;
while ((num = is.read()) != -1 && !((num >= '0' && num <= '9') || num == '-'))
;
if (num == '-') {
num = 0;
minus = true;
} else {
num -= '0';
}
while (true) {
int b = is.read();
if (b >= '0' && b <= '9') {
num = num * 10 + (b - '0');
} else {
return minus ? -num : num;
}
}
} catch (IOException e) {
}
return -1;
}
static char nc() {
try {
int b = skip();
if (b == -1)
return 0;
return (char) b;
} catch (IOException e) {
}
return 0;
}
static double nd() {
try {
return Double.parseDouble(ns());
} catch (Exception e) {
}
return 0;
}
static String ns() {
try {
int b = skip();
StringBuilder sb = new StringBuilder();
if (b == -1)
return "";
sb.append((char) b);
while (true) {
b = is.read();
if (b == -1)
return sb.toString();
if (b <= ' ')
return sb.toString();
sb.append((char) b);
}
} catch (IOException e) {
}
return "";
}
public static char[] ns(int n) {
char[] buf = new char[n];
try {
int b = skip(), p = 0;
if (b == -1)
return null;
buf[p++] = (char) b;
while (p < n) {
b = is.read();
if (b == -1 || b <= ' ')
break;
buf[p++] = (char) b;
}
return Arrays.copyOf(buf, p);
} catch (IOException e) {
}
return null;
}
public static byte[] nse(int n) {
byte[] buf = new byte[n];
try {
int b = skip();
if (b == -1)
return null;
is.read(buf);
return buf;
} catch (IOException e) {
}
return null;
}
static int skip() throws IOException {
int b;
while ((b = is.read()) != -1 && !(b >= 33 && b <= 126))
;
return b;
}
static boolean eof() {
try {
is.mark(1000);
int b = skip();
is.reset();
return b == -1;
} catch (IOException e) {
return true;
}
}
static int ni() {
try {
int num = 0;
boolean minus = false;
while ((num = is.read()) != -1 && !((num >= '0' && num <= '9') || num == '-'))
;
if (num == '-') {
num = 0;
minus = true;
} else {
num -= '0';
}
while (true) {
int b = is.read();
if (b >= '0' && b <= '9') {
num = num * 10 + (b - '0');
} else {
return minus ? -num : num;
}
}
} catch (IOException e) {
}
return -1;
}
static void tr(Object... o) {
if (INPUT.length() != 0)
System.out.println(Arrays.deepToString(o));
}
static long pow(long a, long n) {
long A = a;
long ans = 1;
while (n >= 1) {
if (n % 2 == 0) {
A = A * A;
n /= 2;
} else if (n % 2 == 1) {
ans = ans * A;
n--;
}
}
return ans;
}
}
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