結果
問題 | No.186 中華風 (Easy) |
ユーザー |
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提出日時 | 2024-12-21 02:19:06 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,549 bytes |
コンパイル時間 | 2,261 ms |
コンパイル使用メモリ | 198,220 KB |
最終ジャッジ日時 | 2025-02-26 15:58:07 |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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ファイルパターン | 結果 |
---|---|
other | AC * 21 WA * 2 |
ソースコード
#include<bits/stdc++.h>// #include<atcoder/all>// #include<boost/multiprecision/cpp_int.hpp>using namespace std;// using namespace atcoder;// using bint = boost::multiprecision::cpp_int;using ll = long long;using ull = unsigned long long;using ld = long double;using P = pair<ll,ll>;using vi = vector<ll>;using vvi = vector<vi>;using vvvi = vector<vvi>;using ve = vector<vector<int>>;using vb = vector<bool>;using vvb = vector<vb>;#define rep(i,n) for(ll i = 0;i < (ll)n;i++)#define ALL(x) (x).begin(),(x).end()#define sz(c) ((ll)(c).size())#define LB(A,x) (int)(lower_bound(A.begin(),A.end(),x)-A.begin())#define UB(A,x) (int)(upper_bound(A.begin(),A.end(),x)-A.begin())// #define MOD 1000000007#define MOD 998244353template<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;template<typename T>ostream&operator<<(ostream&os,vector<T>&v){for(int i = 0;i < v.size();i++)os<<v[i]<<(i+1!=v.size()?" ":"");return os;}template<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;}template<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.first<<" "<<p.second;return os;}template<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}template<typename T> inline bool chmax(T &a,T b){if(a < b){a = b;return true;}return false;}template<typename T> inline bool chmin(T &a,T b){if(a > b){a = b;return true;}return false;}ld dist(ld x1,ld y1,ld x2, ld y2){return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));}long long extGcd(long long a, long long b, long long &p, long long &q) {if (b == 0) { p = 1; q = 0; return a; }long long d = extGcd(b, a%b, q, p);q -= a/b * p;return d;}// 解が存在する時、リターン値を (x, M) とすると解は x ≡ r_i (mod M) for all i(M = lcm(m_i))// 解なしの場合は (0, -1)pair<long long, long long> crt(const vector<long long> &r, const vector<long long> &m) {long long x = 0, M = 1;for (int i = 0; i < (int)r.size(); ++i) {long long p, q;long long d = extGcd(M, m[i], p, q); // p is inv of M/d (mod. m[i]/d)if ((r[i] - x) % d != 0) return make_pair(0, -1);long long tmp = (r[i] - x) / d * p % (m[i]/d);x += M * tmp;M *= m[i]/d;}return make_pair((x + M)%M, M);}int main(){ios_base::sync_with_stdio(0), cin.tie(0);vi r(3),m(3);rep(i,3)cin >> r[i] >> m[i];rep(i,3)r[i] %= m[i];auto [x,M] = crt(r,m);if(M == -1)cout << "-1\n";else cout << x << "\n";return 0;}