結果

問題 No.3131 Twin Slide Puzzles
ユーザー 👑 loop0919
提出日時 2024-12-23 05:04:47
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 3,156 bytes
コンパイル時間 468 ms
コンパイル使用メモリ 82,292 KB
実行使用メモリ 232,356 KB
最終ジャッジ日時 2025-04-25 20:51:33
合計ジャッジ時間 38,977 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 32 TLE * 1 -- * 24
権限があれば一括ダウンロードができます

ソースコード

diff # 

from itertools import permutations
from random import shuffle

N = int(input())
A = [list(map(int, input().split())) for _ in range(N)]

class fenwick_tree():
    n=1
    data=[0 for i in range(n)]
    def __init__(self,N):
        self.n=N
        self.data=[0 for i in range(N)]
    def add(self,p,x):
        assert 0<=p<self.n,"0<=p<n,p={0},n={1}".format(p,self.n)
        p+=1
        while(p<=self.n):
            self.data[p-1]+=x
            p+=p& -p
    def sum(self,l,r):
        assert (0<=l and l<=r and r<=self.n),"0<=l<=r<=n,l={0},r={1},n={2}".format(l,r,self.n)
        return self.sum0(r)-self.sum0(l)
    def sum0(self,r):
        s=0
        while(r>0):
            s+=self.data[r-1]
            r-=r&-r
        return s

def serialize(X):
    serialized = []
    for row in X:
        serialized.extend(row)

    return serialized


def calc_parity(X):
    for i in range(len(X)):
        for j in range(len(X)):
            if X[i][j] == 0:
                return (i + j) % 2


def calc_inversion(array):
    MAX = max(array)
    bit = fenwick_tree(MAX + 1)
    
    result = 0
    for a in array:
        result += bit.sum(0, MAX + 1) - bit.sum(0, a + 1)
        bit.add(a, 1)
    
    return result


def is_valid(X):
    parity = calc_parity(X)
    
    serialized = serialize(X)
    inversion = calc_inversion(serialized)
    
    return parity == inversion % 2


def fun(X):
    result = 0
    for i in range(len(X)):
        for j in range(len(X)):
            result += A[i][j] * X[i][j]
    
    return result


def random_pick():
    array = list(range(N**2))
    while True:
        shuffle(array)
        yield array[:]

val = dict()
loop = permutations(range(N**2)) if N <= 3 else random_pick()

if N <= 3:
    for perm in  permutations(range(N**2)):
        X = [[perm[i * N + j] for j in range(N)] for i in range(N)]
        
        if not is_valid(X):
            continue
        
        f = fun(X)
        
        if f in val and X != val[f]:
            print("Yes")
            for row in val[f]:
                print(*row)
            
            for row in X:
                print(*row)
            
            exit()
        
        val[f] = X

else:
    perm = []
    for i in range(4):
        perm.extend([i * N + j for j in range(4)])
    
    while True:
        shuffle(perm)
        X = [[perm[i * 4 + j] for j in range(4)] for i in range(4)]
        
        if not is_valid(X):
            continue
        
        f = fun(X)
        
        if f in val and X != val[f]:
            print("Yes")
            for i in range(N):
                for j in range(N):
                    if i < 4 and j < 4:
                        print(val[f][i][j], end=" ")
                    else:
                        print(i * N + j, end=" ")
                print()
            
            for i in range(N):
                for j in range(N):
                    if i < 4 and j < 4:
                        print(X[i][j], end=" ")
                    else:
                        print(i * N + j, end=" ")
                print()
            
            exit()
        
        val[f] = X

print("No")
0