結果

問題 No.3014 岩井満足性問題
ユーザー 👑 binapbinap
提出日時 2024-12-30 13:43:20
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 2,844 bytes
コンパイル時間 15,469 ms
コンパイル使用メモリ 320,868 KB
実行使用メモリ 6,820 KB
最終ジャッジ日時 2025-01-25 21:54:36
合計ジャッジ時間 16,697 ms
ジャッジサーバーID
(参考情報)
judge10 / judge5
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2 WA * 1
other AC * 15 WA * 3
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return
    os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : "");
    return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return
    true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder
    ::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n -
    1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
// 13:18 Start
// 13:21 Clar
// 13:35 Start implementation
const long long INF = 1001001001001001;
int main(){
int N, D, K;
cin >> N >> D >> K;
vector<int> A(N);
vector<int> C(N);
cin >> A >> C;
vector<vector<long long>> dp(D + 1, vector<long long>(K + 1, -INF));
dp[0][0] = 0;
rep(i, N){
for(int j = D - 1; j >= 0; j--){
for(int k = K; k >= 0; k--){
if(dp[j][k] == -INF) continue;
chmax(dp[j + 1][min(k + C[i], K)], dp[j][k] + A[i]);
}
}
}
long long ans = dp[D][K];
if(ans == -INF) cout << "-1\n";
else cout << ans << "\n";
return 0;
}
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