#1036029 (C++23) No.3002 多項式の割り算 〜easy〜

• 問題: No.3002 多項式の割り算 〜easy〜
• ユーザー: friedrice
• 提出日時: 2025-01-17 22:55:29
• 言語: C++23 (gcc 13.3.0 + boost 1.87.0)
• 結果: AC
• 実行時間: 2 ms / 2,000 ms
• コード長: 2,095 bytes
• コンパイル時間: 8,208 ms
• コンパイル使用メモリ: 332,416 KB
• 実行使用メモリ: 5,248 KB
• 最終ジャッジ日時: 2025-01-17 22:56:24
• 合計ジャッジ時間: 7,760 ms
• ジャッジサーバーID （参考情報）: judge1 / judge4

ファイルパターン	結果
sample	AC * 2
other	AC * 22

ソースコード

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#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using ll = long long;
using ull = unsigned long long;
using mint = atcoder::modint998244353;
using maxt = atcoder::modint1000000007;
vector<ll> Era(int N) {
  vector<ll> ans(0, 0);
  vector<bool> isprime(N + 1, true);
  isprime.at(1) = false;
  for(int i = 1; i <= N; i++) {
    if(isprime.at(i)) {
      ans.push_back(i);
      for(int j = 2 * i; j <= N; j += i) {
        isprime.at(j) = false;
      }
    }
  }
  return ans;
}
ll POW(ll a, int N) {
  if(N == 1) {
    return a;
  }
  ll ans = POW(a, N / 2) * POW(a, N / 2);
  if(N % 2 == 1) {
    ans *= a;
  }
  return ans;
}
ll GCD(ll a, ll b) {
  if(b == 0) {
    return a;
  }
  int r = a % b;
  return GCD(b, r);
}
ll LCM(ll a, ll b) {
  return (a * b) / GCD(a, b);
}
vector<ll> zaatu(vector<ll> a) {
  vector<ll> b(0, 0);
  b = a;
  sort(b.begin(), b.end());
  b.erase(unique(b.begin(), b.end()), b.end());
  int s = b.size();
  for(ll &o : a) {
    int l = 0, r = s, c = 0;
    while(r - l > 1) {
      c = (l + r) / 2;
      if(b.at(c) <= o) {
        l = c;
      }
      else {
        r = c;
      }
    }
    o = r;
  }
  return a;
}
struct FenwickTree {
  int N;
  vector<ll> a;
  
  FenwickTree(int n) {
    N = n;
    a.assign(N + 1, 0);
  }
  
  void add(int i, ll x) {
    for(int j = i; j <= N; j += (j & -j)) {
      a.at(j) += x;
    }
  }
  
  ll sum(int i, int j) {
    return sum_sub(j) - sum_sub(i - 1);
  }
  
  ll sum_sub(int i) {
    if(i == 0) {
      return 0;
    }
    ll s = 0;
    for(int j = i; j > 0; j -= (j & -j)) {
      s += a.at(j);
    }
    return s;
  }
};
ll tento(vector<ll> a) {
  int s = a.size();
  FenwickTree tmp(s);
  ll ans = 0;
  for(int i = 0; i < s; i++) {
    ans += i - tmp.sum_sub(a.at(i));
    tmp.add(a.at(i), 1);
  }
  return ans;
}
//__builtin_popcount
//next_permutation
//srand((unsigned)time(NULL))
//library end
int main() {
    int A, B;
    cin >> A >> B;
    if(B % 3 == 0) {
        cout << "0 " << A << endl;
    }
    else if(B % 3 == 1) {
        cout << A << " 0" << endl;
    }
    else {
        cout << -A << ' ' << -A << endl;
    }
}
 
 
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