結果
問題 | No.3004 ヤング図形 |
ユーザー |
👑 |
提出日時 | 2025-01-17 23:02:11 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
MLE
|
実行時間 | - |
コード長 | 3,480 bytes |
コンパイル時間 | 4,172 ms |
コンパイル使用メモリ | 254,376 KB |
実行使用メモリ | 817,956 KB |
最終ジャッジ日時 | 2025-01-17 23:03:11 |
合計ジャッジ時間 | 42,356 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 7 TLE * 3 MLE * 15 |
ソースコード
#include<bits/stdc++.h>#include<atcoder/all>#define rep(i,n) for(int i=0;i<n;i++)using namespace std;using namespace atcoder;typedef long long ll;typedef vector<int> vi;typedef vector<long long> vl;typedef vector<vector<int>> vvi;typedef vector<vector<long long>> vvl;typedef long double ld;typedef pair<int, int> P;template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); returnos;}template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : "");return os;}template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){returntrue;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n -1 ? "\n" : " "); return os;}template<typename T> void chmin(T& a, T b){a = min(a, b);}template<typename T> void chmax(T& a, T b){a = max(a, b);}using mint = modint998244353;// combination mod prime// https://youtu.be/8uowVvQ_-Mo?t=6002// https://youtu.be/Tgd_zLfRZOQ?t=9928struct modinv {int n; vector<mint> d;modinv(): n(2), d({0,1}) {}mint operator()(int i) {while (n <= i) d.push_back(-d[mint::mod()%n]*(mint::mod()/n)), ++n;return d[i];}mint operator[](int i) const { return d[i];}} invs;struct modfact {int n; vector<mint> d;modfact(): n(2), d({1,1}) {}mint operator()(int i) {while (n <= i) d.push_back(d.back()*n), ++n;return d[i];}mint operator[](int i) const { return d[i];}} facts;struct modfactinv {int n; vector<mint> d;modfactinv(): n(2), d({1,1}) {}mint operator()(int i) {while (n <= i) d.push_back(d.back()*invs(n)), ++n;return d[i];}mint operator[](int i) const { return d[i];}} ifacts;mint comb(int n, int k) {if (n < k || k < 0) return 0;return facts(n)*ifacts(k)*ifacts(n-k);}int main(){int k;cin >> k;vector<int> l(k), m(k);rep(i, k) cin >> l[i] >> m[i];int n = 0;rep(i, k) n += l[i] * m[i];mint ans = facts(n);rep(i, k){ans *= ifacts(l[i]).pow(m[i]);ans *= ifacts(m[i]);}cout << ans << "\n";return 0;}