結果
問題 | No.3010 水色コーダーさん |
ユーザー |
![]() |
提出日時 | 2025-01-25 12:47:49 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 115 ms / 2,000 ms |
コード長 | 1,949 bytes |
コンパイル時間 | 313 ms |
コンパイル使用メモリ | 82,916 KB |
実行使用メモリ | 78,020 KB |
最終ジャッジ日時 | 2025-01-25 22:21:33 |
合計ジャッジ時間 | 3,803 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge8 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 20 |
ソースコード
import sys input = lambda: sys.stdin.readline().rstrip() # sys.setrecursionlimit(10**7) # sys.set_int_max_str_digits(10**6) # import pypyjit # pypyjit.set_param('max_unroll_recursion=-1') def mp():return map(int,input().split()) def lmp():return list(map(int,input().split())) def lm1(LIST): return list(map(lambda x:x-1, LIST)) def mps(A):return [tuple(map(int, input().split())) for _ in range(A)] def stoi(LIST):return list(map(int,LIST)) def itos(LIST):return list(map(str,LIST)) def atoi(LIST): return [ord(i)-ord("a") for i in LIST] def Atoi(LIST): return [ord(i)-ord("A") for i in LIST] def LT(LIST,N): return LIST[bisect.bisect_left(LIST,N)-1] def LE(LIST,N): return LIST[bisect.bisect_right(LIST,N)-1] def GT(LIST,N): return LIST[bisect.bisect_right(LIST,N)] def GE(LIST,N): return LIST[bisect.bisect_left(LIST,N)] def bitA(X,A):return X & 1<<A == 1<<A def gtoi(x,y,h,w):return x*w+y import math import bisect import heapq import time import random as rd import itertools from copy import copy as cc from copy import deepcopy as dc from itertools import accumulate, product from collections import Counter, defaultdict, deque # from atcoder.dsu import DSU # from atcoder.fenwicktree import FenwickTree # from atcoder.segtree import SegTree # (op, ide_ele, LIST) # from atcoder.lazysegtree import LazySegTree # (op, ide_ele, mapping, composition, _id, lst) def ceil(U,V):return (U+V-1)//V def modf1(N,MOD):return (N-1)%MOD+1 def pmat(list): for i in list:print(*i) m4 = [[1,0],[0,1],[-1,0],[0,-1]] m8 = [[-1,-1],[-1,0],[-1,1],[0,-1],[0,1],[1,-1],[1,0],[1,1]] inf = (1<<63)-1 mod = 998244353 n,m = mp() ans = 0 for i in range(n): u,v = map(str,input().split()) v = int(v) if v >= 1200 and u[:4].count("o") != 4: ans += 1 print(ans) # n = int(input()) # ok = 0 # ng = 10**9+1 # while (ok-ng) != 1: # m = (ok+ng)//2 # print(m) # ans = int(input()) # if ans == 1: # exit() # elif ans == 0: