結果
問題 | No.3017 交互浴 |
ユーザー |
|
提出日時 | 2025-01-25 13:09:26 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 286 ms / 2,000 ms |
コード長 | 3,166 bytes |
コンパイル時間 | 2,383 ms |
コンパイル使用メモリ | 209,784 KB |
実行使用メモリ | 12,680 KB |
最終ジャッジ日時 | 2025-01-25 22:34:48 |
合計ジャッジ時間 | 19,479 ms |
ジャッジサーバーID (参考情報) |
judge11 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 55 |
ソースコード
#include <bits/stdc++.h>using namespace std;template<typename T>vector<T> zaatu(vector<T> &A){//座標圧縮=Compress.vector<T> B = A;sort(B.begin(),B.end());B.erase(unique(B.begin(),B.end()),B.end());for(auto &a : A) a = lower_bound(B.begin(),B.end(),a)-B.begin();return B;}using SS = pair<int,int>;using FF = int;class LazySegmentTree{public:int siz = 1;vector<SS> dat;vector<FF> lazy;FF ID = -1;SS op(SS a,SS b){return {a.first+b.first,a.second+b.second};}SS mapping(FF f, SS x){if(f == -1) return x;return {x.second*f,x.second};}FF composition(FF f, FF g){if(f == -1) return g;if(g == -1) return f;return f;}SS e(){return {0,0};}FF id(){return ID;}//op区間演算 mapping lazy→data composition lazy→lazy//e 単位元 id map(id,a)=avoid make(int N){while(siz < N) siz *= 2;dat.resize(siz*2,e());lazy.resize(siz*2,ID);}void make2(int N,vector<SS> &A){make(N);for(int i=0; i<N; i++){int pos = i+siz-1;dat.at(pos) = A.at(i);}for(int i=siz-2; i>=0; i--) dat.at(i) = op(dat.at(i*2+1),dat.at(i*2+2));}void eval(int u,int a,int b){if(id() != lazy.at(u)){dat.at(u) = mapping(lazy.at(u),dat.at(u));if(b-a > 1){lazy.at(u*2+1) = composition(lazy.at(u),lazy.at(u*2+1));lazy.at(u*2+2) = composition(lazy.at(u),lazy.at(u*2+2));}lazy.at(u) = id();}}void findadd(int L,int R,int a,int b,int u,FF x){eval(u,a,b);if(R <= a || b <= L) return;if(L <= a && b <= R){lazy.at(u) = composition(x,lazy.at(u));eval(u,a,b);}else{findadd(L,R,a,(a+b)/2,u*2+1,x);findadd(L,R,(a+b)/2,b,u*2+2,x);dat.at(u) = op(dat.at(u*2+1),dat.at(u*2+2));}}void update(int L,int R,FF x){findadd(L,R,0,siz,0,x);}SS findans(int L,int R,int a,int b,int u){if(R <= a || b <= L) return e();eval(u,a,b);if(L <= a && b <= R) return dat.at(u);return op(findans(L,R,a,(a+b)/2,u*2+1),findans(L,R,(a+b)/2,b,u*2+2));}SS get(int pos){return findans(pos,pos+1,0,siz,0);}SS rangeans(int l,int r){return findans(l,r,0,siz,0);}SS allrange(){return findans(0,siz,0,siz,0);}};int main(){ios_base::sync_with_stdio(false);cin.tie(nullptr);int N; cin >> N;vector<int> H(N);for(auto &h : H) cin >> h;auto H2 = H;sort(H2.begin(),H2.end());H2.erase(unique(H2.begin(),H2.end()),H2.end());int n = H2.size();vector<SS> give;{int x = 0;for(int i=0; i<n; i++) give.push_back({0,H2.at(i)-x}),x = H2.at(i);}LazySegmentTree Z; Z.make2(n,give);bool cyan = true;for(auto &h : H){h = lower_bound(H2.begin(),H2.end(),h)-H2.begin();Z.update(0,h+1,cyan);cout << Z.allrange().first << "\n";cyan ^= 1;}}