結果
| 問題 |
No.3013 ハチマキ買い星人
|
| コンテスト | |
| ユーザー |
みやべ
|
| 提出日時 | 2025-01-25 17:25:49 |
| 言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 225 ms / 2,000 ms |
| コード長 | 7,409 bytes |
| コンパイル時間 | 6,117 ms |
| コンパイル使用メモリ | 428,688 KB |
| 実行使用メモリ | 25,100 KB |
| 最終ジャッジ日時 | 2025-01-25 23:58:18 |
| 合計ジャッジ時間 | 13,017 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 45 |
ソースコード
#ifdef sys
#define _GLIBCXX_DEBUG
#endif
#include <bits/stdc++.h>
using namespace std;
using ull = unsigned long long;
using ll = long long;
using ld = long double;
using lll = __int128;
using llld = _Float128;
#define el "\n"
#define all(x) x.begin(), x.end()
#define initv2(t,a,...) a, vector<t>(__VA_ARGS__)
#define initv3(t,a,b,...) a, vector<vector<t>>(b, vector<t>(__VA_ARGS__))
#define pair(a,b) pair<a, b>
#define COUNT(a,b) count_if(a, [&](auto _Cx){return _Cx b;})
#define vec vector
#define elif else if
namespace Myb{
long long LLINF = 1010101010101010101;
int INF = 1010101010;
namespace Myb_ios{
template<typename T, typename U>
istream& operator>>(istream& ist, pair<T, U>& p) {cin >> p.first >> p.second; return ist;}
template<typename T>
istream& operator>>(istream& ist, vector<T>& v) {for(T& i : v) cin >> i; return ist;}
istream& operator>>(istream& ist, _Float128& x) {long double n; cin >> n; x = n; return ist;}
void read_d_graph(vector<vector<pair<long long, int>>>& v, int m, int num = -1){
int a, b; long long c;
for(int _ = 0; _ < m; _++){
cin >> a >> b >> c;
a += num; b += num;
v[a].emplace_back(c, b);
} return;
}
void read_d_graph(vector<vector<int>>& v, int m, int num = -1){
int a, b;
for(int _ = 0; _ < m; _++){
cin >> a >> b;
a += num; b += num;
v[a].emplace_back(b);
} return;
}
void read_ud_graph(vector<vector<pair<long long, int>>>& v, int m, int num = -1){
int a, b; long long c;
for(int _ = 0; _ < m; _++){
cin >> a >> b >> c;
a += num; b += num;
v[a].emplace_back(c, b);
v[b].emplace_back(c, a);
} return;
}
void read_ud_graph(vector<vector<int>>& v, int m, int num = -1){
int a, b;
for(int _ = 0; _ < m; _++){
cin >> a >> b;
a += num; b += num;
v[a].emplace_back(b);
v[b].emplace_back(a);
} return;
}
template<typename T>
void read_multi(T& v, int n) {}
template<typename T, typename... U>
void read_multi(T& v, int n, U&&... args){
if(n >= v.size()) read_multi(args...);
else {
cin >> v[n];
read_multi(args..., v, n+1);
}
}
string input() {string res; cin >> res; return res;}
long long inputl() {long long res; cin >> res; return res;}
template<typename T, typename U>
ostream& operator<<(ostream& ost, const pair<T, U> p) {cerr << "{"; ost << p.first << " " << p.second; cerr << "}"; return ost;}
template<typename T>
ostream& operator<<(ostream& ost, const vector<T>& v) {for(int i = 0; i < v.size(); i++) {if(i) ost << " "; ost << v[i];} return ost;}
template<typename T>
ostream& operator<<(ostream& ost, const vector<vector<T>>& v) {for(int i = 0; i < v.size(); i++) {if(i) ost << "\n"; ost << v[i];} return ost;}
} using namespace Myb_ios;
long long add_each(long long n) {return n;}
template<typename T, typename... U>
void add_each(long long n, vector<T>& v, U&... args) {
for(auto& i : v) i += n;
add_each(n, args...);
}
template<typename T, typename U> bool chmin(T& a, U b) {if(a > b){a = b; return true;} return false;}
template<typename T, typename U> bool chmax(T& a, U b) {if(a < b){a = b; return true;} return false;}
template<typename T> T minv(const vector<T>& v) {return *min_element(v.begin(), v.end());}
template<typename T> T maxv(const vector<T>& v) {return *max_element(v.begin(), v.end());}
long long power(long long val, long long num, long long mod = LLONG_MAX){
assert(mod > 0); assert(num >= 0);
val %= mod;
long long res = 1;
if(mod < INT_MAX || mod == LLONG_MAX){
while(num){
if(num&1) res = (res*val)%mod;
val = (val*val)%mod;
num >>= 1;
}
} else {
while(num){
if(num&1) res = (__int128(res)*val)%mod;
val = (__int128(val)*val)%mod;
num >>= 1;
}
}
return res;
}
long long comb(long long N, long long K, int mod = 0){
const int COMBSIZ = 200000;
assert(mod >= 0);
if(N < K || K < 0) return 0;
static vector<long long> combf(COMBSIZ+9, -1);
long long res;
if(mod != 0){
assert(N <= COMBSIZ);
if(combf[0] == -1){
combf[0] = 1;
for(long long i = 1; i <= COMBSIZ; i++) combf[i] = (combf[i-1]*i)%mod;
}
res = (combf[N]*power((combf[N-K]*combf[K])%mod, mod-2, mod))%mod;
return res;
} else {
long long a=1, b=1;
K = min(K, N-K);
for(long long i = N; i > N-K; i--) a *= i;
for(long long i = 2; i <= K; i++) b *= i;
return a/b;
}
}
} using namespace Myb;
#if __has_include(<atcoder/all>)
#include <atcoder/modint>
using namespace atcoder;
using mint9 = modint998244353;
using mint1 = modint1000000007;
ostream& operator<<(ostream& ost, const mint1& x) {ost << x.val(); return ost;}
ostream& operator<<(ostream& ost, const mint9& x) {ost << x.val(); return ost;}
ostream& operator<<(ostream& ost, const modint& x) {ost << x.val(); return ost;}
#endif
/*vvv^vvvv^vvvvv^^^^^^^^^vv^^^^^^vvvvv^^^vvvvv^^^^^^^^vvvvvvvvv^^^^^^^vvvvvvvvv^^^vv^^^vvvvvvvv^^^^vvvvvv^^vvvvvv^^^^vvv^^^vvvvvvvv^^^vv^^^^^^^vvvvvvvvv^^^^^_^^vvvvvvvv^^^^^^^^vvvv^vvvvvvvvv^^^^^^^v*/
signed main(){
ios::sync_with_stdio(0); cin.tie(0);
int n, m, p, u, v;
ll y, c;
cin >> n >> m >> p >> y;
vec<vec<pair<ll, int>>> G(n);
map<pair<int, int>, ll> M;
for(int i = 0; i < m; i++){
cin >> u >> v >> c;
u--; v--;
G[u].emplace_back(c, v);
G[v].emplace_back(c, u);
}
vec<ll> S(n, LLINF);
for(int i = 0; i < p; i++){
cin >> u >> c;
u--;
chmin(S[u], c);
}
auto dijkstra = [](const vector<vector<pair<long long, int>>>& v, const vector<int>& s){
int siz = v.size();
vector<long long> dist(siz, LLINF);
vector<int> path(siz, -1);
priority_queue<pair<long long, int>, vector<pair<long long, int>>, greater<pair<long long, int>>> pq;
for(int i : s){
dist[i] = 0;
pq.emplace(0, i);
}
while(!pq.empty()){
auto [d, pos] = pq.top();
pq.pop();
if(d > dist[pos]) continue;
for(auto [cost, nex] : v[pos]){
long long nex_cost = dist[pos] + cost;
if(dist[nex] > nex_cost){
dist[nex] = nex_cost;
pq.emplace(dist[nex], nex);
path[nex] = pos;
}
}
}
return make_pair(dist, path);
};
auto dist = dijkstra(G, {0}).first;
ll ans = 0;
for(int i = 0; i < n; i++){
chmax(ans, (y-dist[i])/S[i]);
}
cout << ans << el;
}
みやべ