結果
問題 |
No.3013 ハチマキ買い星人
|
ユーザー |
|
提出日時 | 2025-01-25 17:25:49 |
言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 225 ms / 2,000 ms |
コード長 | 7,409 bytes |
コンパイル時間 | 6,117 ms |
コンパイル使用メモリ | 428,688 KB |
実行使用メモリ | 25,100 KB |
最終ジャッジ日時 | 2025-01-25 23:58:18 |
合計ジャッジ時間 | 13,017 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 45 |
ソースコード
#ifdef sys #define _GLIBCXX_DEBUG #endif #include <bits/stdc++.h> using namespace std; using ull = unsigned long long; using ll = long long; using ld = long double; using lll = __int128; using llld = _Float128; #define el "\n" #define all(x) x.begin(), x.end() #define initv2(t,a,...) a, vector<t>(__VA_ARGS__) #define initv3(t,a,b,...) a, vector<vector<t>>(b, vector<t>(__VA_ARGS__)) #define pair(a,b) pair<a, b> #define COUNT(a,b) count_if(a, [&](auto _Cx){return _Cx b;}) #define vec vector #define elif else if namespace Myb{ long long LLINF = 1010101010101010101; int INF = 1010101010; namespace Myb_ios{ template<typename T, typename U> istream& operator>>(istream& ist, pair<T, U>& p) {cin >> p.first >> p.second; return ist;} template<typename T> istream& operator>>(istream& ist, vector<T>& v) {for(T& i : v) cin >> i; return ist;} istream& operator>>(istream& ist, _Float128& x) {long double n; cin >> n; x = n; return ist;} void read_d_graph(vector<vector<pair<long long, int>>>& v, int m, int num = -1){ int a, b; long long c; for(int _ = 0; _ < m; _++){ cin >> a >> b >> c; a += num; b += num; v[a].emplace_back(c, b); } return; } void read_d_graph(vector<vector<int>>& v, int m, int num = -1){ int a, b; for(int _ = 0; _ < m; _++){ cin >> a >> b; a += num; b += num; v[a].emplace_back(b); } return; } void read_ud_graph(vector<vector<pair<long long, int>>>& v, int m, int num = -1){ int a, b; long long c; for(int _ = 0; _ < m; _++){ cin >> a >> b >> c; a += num; b += num; v[a].emplace_back(c, b); v[b].emplace_back(c, a); } return; } void read_ud_graph(vector<vector<int>>& v, int m, int num = -1){ int a, b; for(int _ = 0; _ < m; _++){ cin >> a >> b; a += num; b += num; v[a].emplace_back(b); v[b].emplace_back(a); } return; } template<typename T> void read_multi(T& v, int n) {} template<typename T, typename... U> void read_multi(T& v, int n, U&&... args){ if(n >= v.size()) read_multi(args...); else { cin >> v[n]; read_multi(args..., v, n+1); } } string input() {string res; cin >> res; return res;} long long inputl() {long long res; cin >> res; return res;} template<typename T, typename U> ostream& operator<<(ostream& ost, const pair<T, U> p) {cerr << "{"; ost << p.first << " " << p.second; cerr << "}"; return ost;} template<typename T> ostream& operator<<(ostream& ost, const vector<T>& v) {for(int i = 0; i < v.size(); i++) {if(i) ost << " "; ost << v[i];} return ost;} template<typename T> ostream& operator<<(ostream& ost, const vector<vector<T>>& v) {for(int i = 0; i < v.size(); i++) {if(i) ost << "\n"; ost << v[i];} return ost;} } using namespace Myb_ios; long long add_each(long long n) {return n;} template<typename T, typename... U> void add_each(long long n, vector<T>& v, U&... args) { for(auto& i : v) i += n; add_each(n, args...); } template<typename T, typename U> bool chmin(T& a, U b) {if(a > b){a = b; return true;} return false;} template<typename T, typename U> bool chmax(T& a, U b) {if(a < b){a = b; return true;} return false;} template<typename T> T minv(const vector<T>& v) {return *min_element(v.begin(), v.end());} template<typename T> T maxv(const vector<T>& v) {return *max_element(v.begin(), v.end());} long long power(long long val, long long num, long long mod = LLONG_MAX){ assert(mod > 0); assert(num >= 0); val %= mod; long long res = 1; if(mod < INT_MAX || mod == LLONG_MAX){ while(num){ if(num&1) res = (res*val)%mod; val = (val*val)%mod; num >>= 1; } } else { while(num){ if(num&1) res = (__int128(res)*val)%mod; val = (__int128(val)*val)%mod; num >>= 1; } } return res; } long long comb(long long N, long long K, int mod = 0){ const int COMBSIZ = 200000; assert(mod >= 0); if(N < K || K < 0) return 0; static vector<long long> combf(COMBSIZ+9, -1); long long res; if(mod != 0){ assert(N <= COMBSIZ); if(combf[0] == -1){ combf[0] = 1; for(long long i = 1; i <= COMBSIZ; i++) combf[i] = (combf[i-1]*i)%mod; } res = (combf[N]*power((combf[N-K]*combf[K])%mod, mod-2, mod))%mod; return res; } else { long long a=1, b=1; K = min(K, N-K); for(long long i = N; i > N-K; i--) a *= i; for(long long i = 2; i <= K; i++) b *= i; return a/b; } } } using namespace Myb; #if __has_include(<atcoder/all>) #include <atcoder/modint> using namespace atcoder; using mint9 = modint998244353; using mint1 = modint1000000007; ostream& operator<<(ostream& ost, const mint1& x) {ost << x.val(); return ost;} ostream& operator<<(ostream& ost, const mint9& x) {ost << x.val(); return ost;} ostream& operator<<(ostream& ost, const modint& x) {ost << x.val(); return ost;} #endif /*vvv^vvvv^vvvvv^^^^^^^^^vv^^^^^^vvvvv^^^vvvvv^^^^^^^^vvvvvvvvv^^^^^^^vvvvvvvvv^^^vv^^^vvvvvvvv^^^^vvvvvv^^vvvvvv^^^^vvv^^^vvvvvvvv^^^vv^^^^^^^vvvvvvvvv^^^^^_^^vvvvvvvv^^^^^^^^vvvv^vvvvvvvvv^^^^^^^v*/ signed main(){ ios::sync_with_stdio(0); cin.tie(0); int n, m, p, u, v; ll y, c; cin >> n >> m >> p >> y; vec<vec<pair<ll, int>>> G(n); map<pair<int, int>, ll> M; for(int i = 0; i < m; i++){ cin >> u >> v >> c; u--; v--; G[u].emplace_back(c, v); G[v].emplace_back(c, u); } vec<ll> S(n, LLINF); for(int i = 0; i < p; i++){ cin >> u >> c; u--; chmin(S[u], c); } auto dijkstra = [](const vector<vector<pair<long long, int>>>& v, const vector<int>& s){ int siz = v.size(); vector<long long> dist(siz, LLINF); vector<int> path(siz, -1); priority_queue<pair<long long, int>, vector<pair<long long, int>>, greater<pair<long long, int>>> pq; for(int i : s){ dist[i] = 0; pq.emplace(0, i); } while(!pq.empty()){ auto [d, pos] = pq.top(); pq.pop(); if(d > dist[pos]) continue; for(auto [cost, nex] : v[pos]){ long long nex_cost = dist[pos] + cost; if(dist[nex] > nex_cost){ dist[nex] = nex_cost; pq.emplace(dist[nex], nex); path[nex] = pos; } } } return make_pair(dist, path); }; auto dist = dijkstra(G, {0}).first; ll ans = 0; for(int i = 0; i < n; i++){ chmax(ans, (y-dist[i])/S[i]); } cout << ans << el; }