結果
問題 | No.484 収穫 |
ユーザー |
|
提出日時 | 2025-01-28 23:59:21 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 1,532 ms / 3,000 ms |
コード長 | 1,400 bytes |
コンパイル時間 | 1,628 ms |
コンパイル使用メモリ | 160,492 KB |
実行使用メモリ | 74,496 KB |
最終ジャッジ日時 | 2025-01-28 23:59:46 |
合計ジャッジ時間 | 20,156 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 21 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:40:15: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 40 | scanf ("%lld", &n); | ~~~~~~^~~~~~~~~~~~ main.cpp:42:46: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 42 | for (int i = 1; i <= n; i ++ ) scanf ("%lld", &a[i]), mx = max (mx, a[i]); | ~~~~~~^~~~~~~~~~~~~~~
ソースコード
# include <bits/stdc++.h> using namespace std; typedef long long ll; # define int long long # define lc u << 1 # define rc u << 1 | 1 # define fi first # define se second const int N = 2005; int n; int a[N]; int f[N][N][2]; bool vis[N][N][2]; int dfs (int l, int r, int x, int mid) { if (vis[l][r][x]) return f[l][r][x]; vis[l][r][x] = 1; if (l == r) return f[l][r][x] = mid; if (!x) { int t = dfs (l + 1, r, 0, mid); if (a[l] < t) f[l][r][x] = max (f[l][r][x], t - 1); t = dfs (l, r - 1, 1, mid); if (a[r] < t) f[l][r][x] = max (f[l][r][x], t - (r - l + 1)); } else { int t = dfs (l + 1, r, 0, mid); if (a[l] < t) f[l][r][x] = max (f[l][r][x], t - (r - l + 1)); t = dfs (l, r - 1, 1, mid); if (a[r] < t) f[l][r][x] = max (f[l][r][x], t - 1); } return f[l][r][x]; } signed main () { // freopen ("apple.in", "r", stdin); // freopen ("apple.out", "w", stdout); scanf ("%lld", &n); int mx = 0; for (int i = 1; i <= n; i ++ ) scanf ("%lld", &a[i]), mx = max (mx, a[i]); int l = mx, r = 2e9, ans = 0; while (l <= r) { int mid = l + r >> 1; for (int i = 1; i <= n; i ++ ) { for (int j = 1; j <= n; j ++ ) { for (int k = 0; k <= 1; k ++ ) f[i][j][k] = -1e18, vis[i][j][k] = 0; } } if (dfs (1, n, 0, mid) >= 0 || dfs (1, n, 1, mid) >= 0) r = mid - 1, ans = mid; else l = mid + 1; } printf ("%lld\n", ans); return 0; }