結果

問題 No.3076 Goodstuff Deck Builder
ユーザー 👑 binap
提出日時 2025-02-10 20:08:50
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 88 ms / 3,000 ms
コード長 2,907 bytes
コンパイル時間 4,475 ms
コンパイル使用メモリ 258,620 KB
実行使用メモリ 7,324 KB
最終ジャッジ日時 2025-03-28 20:50:10
合計ジャッジ時間 6,940 ms
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 36
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;

template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}

template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}

const int K = 10;

int main(){
	int N, M;
	cin >> N >> M;
	vector<pair<int, int>> hand;
	long long ans1 = 0;
	rep(i, N){
		int C, D;
		cin >> C >> D;
		if(C == 0) ans1 += D;
		else hand.emplace_back(C, D);
	}
	sort(hand.rbegin(), hand.rend());
	
	vector<vector<long long>> dp(K + 1, vector<long long>(M + 1, 0LL));
	for(auto [_C, D] : hand){
		for(int i = K - 1; i >= 0; i--){
			int C = (_C << i);
			for(int j = M - C; j >= 0; j--){
				chmax(dp[i + 1][j + C], dp[i][j] + D); 
			}
		}
	}
	long long ans2 = 0;
	for(int i = 0; i <= K; i++) for(int j = 0; j <= M; j++) chmax(ans2, dp[i][j]);
	cout << ans1 + ans2 << "\n";
	return 0;
}
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