結果

問題 No.3047 Verification of Sorting Network
ユーザー amentorimaru
提出日時 2025-02-10 21:25:05
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 257 ms / 2,000 ms
コード長 5,052 bytes
コンパイル時間 4,674 ms
コンパイル使用メモリ 270,096 KB
実行使用メモリ 8,608 KB
最終ジャッジ日時 2025-03-05 20:39:03
合計ジャッジ時間 17,770 ms
ジャッジサーバーID
(参考情報)
judge3 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 61
権限があれば一括ダウンロードができます

ソースコード

diff #

#define ATCODER
#define _USE_MATH_DEFINES
#include<stdio.h>
#include <bit>
#include <cstdint>
#include<iostream>
#include<fstream>
#include<algorithm>
#include<vector>
#include<string>
#include <cassert>
#include <numeric>
#include <unordered_map>
#include <unordered_set>
#include <queue>
#include <math.h>
#include <climits>
#include <set>
#include <map>
#include <list>
#include <random>
#include <iterator>
#include <bitset>
#include <chrono>
#include <type_traits>
using namespace std;

using ll = long long;
using ld = long double;
using pll = pair<ll, ll>;
using pdd = pair<ld, ld>;

//template<claLR T> using pq = priority_queue<T, vector<T>, greater<T>>;

#define FOR(i, a, b) for(ll i=(a); i<(b);i++)
#define REP(i, n) for(ll i=0; i<(n);i++)
#define ROF(i, a, b) for(ll i=(b-1); i>=(a);i--)
#define PER(i, n) for(ll i=n-1; i>=0;i--)
#define REPREP(i,j,a,b) for(ll i=0;i<a;i++)for(ll j=0;j<b;j++)
#define VV(type) vector< vector<type> >
#define VV2(type,n,m,val) vector< vector<type> > val;val.resize(n);for(ll i;i<n;i++)val[i].resize(m)
#define vec(type) vector<type>
#define VEC(type,n,val) vector<type> val;val.resize(n)
#define VL vector<ll>
#define VVL vector< vector<ll> >
#define VP vector< pair<ll,ll> >
#define SZ size()
#define all(i) begin(i),end(i)
#define SORT(i) sort(all(i))
#define BITI(i) (1<<i)
#define BITSET(x,i) x | (ll(1)<<i)
#define BITCUT(x,i) x & ~(ll(1)<<i)
#define EXISTBIT(x,i) (((x>>i) & 1) != 0)
#define ALLBIT(n) (ll(1)<<n-1)
#define CHMAX(n,v) n=n<v?v:n
#define CHMIN(n,v) n=n>v?v:n
#define MP(a,b) make_pair(a,b)
#define DET2(x1,y1,x2,y2) (x1)*(y2)-(x2)*(y1)
#define DET3(x1,y1,z1,x2,y2,z2,x3,y3,z3) (x1)*(y2)*(z3)+(x2)*(y3)*(z1)+(x3)*(y1)*(z2)-(z1)*(y2)*(x3)-(z2)*(y3)*(x1)-(z3)*(y1)*(x2)
#define INC(a) for(auto& v:a)v++;
#define DEC(a) for(auto& v:a)v--;
#define SQU(x) (x)*(x)
#define L0 ll(0)
#ifdef ATCODER
#include <atcoder/all>
using namespace atcoder;
//using mint = modint1000000007;
using mint2 = modint998244353;
#endif
template<typename T = ll>
vector<T> read(size_t n) {
  vector<T> ts(n);
  for (size_t i = 0; i < n; i++) cin >> ts[i];
  return ts;
}

template<typename TV, const ll N> void read_tuple_impl(TV&) {}
template<typename TV, const ll N, typename Head, typename... Tail>
void read_tuple_impl(TV& ts) {
  get<N>(ts).emplace_back(*(istream_iterator<Head>(cin)));
  read_tuple_impl<TV, N + 1, Tail...>(ts);
}
template<typename... Ts> decltype(auto) read_tuple(size_t n) {
  tuple<vector<Ts>...> ts;
  for (size_t i = 0; i < n; i++) read_tuple_impl<decltype(ts), 0, Ts...>(ts);
  return ts;
}

using val = ll;
using func = ll;

val op(val a, val b) {
  return a + b;
}


val e() { return 0; }

val mp(func f, val a)
{
  return a + f;
}
func comp(func f, func g) {
  return f + g;
}

func id() {
  return 0;
}

ll g;
bool f(val a) {
  return a < g;
}

ll di[4] = { 1,0,-1,0 };
ll dj[4] = { 0,1,0,-1 };
ll si[4] = { 0,3,3,0 };
ll sj[4] = { 0,0,3,3 };
//ll di[4] = { -1,-1,1,1 };
//ll dj[4] = { -1,1,-1,1 };
//ll di8[8] = { 0,-1,-1,-1,0,1,1,1 };
//ll dj8[8] = { -1,-1,0,1,1,1,0,-1 };


void solve() {
  ll n, m;
  cin >> n >> m;
  VL a = read(m);
  VL b = read(m);
  DEC(a); DEC(b);

  bool isOk = true;
  vector<bool> ans0(m); // 使われる機会があるか
  vector<bool> ans1(n); // 逆転の可能性があるか

  auto dfs = [&](auto self, ll now, VL& arr) -> void {
    if (now == m) {
      REP(i, n - 1) {
        if (arr[i] > arr[i + 1]) {
          isOk = false;
          ans1[i] = true;
        }
        if (arr[i] == 1 && arr[i + 1] == 1) {
          isOk = false;
          ans1[i] = true;
        }
      }
      return;
    }
    if (arr[a[now]] == 0 || arr[b[now]] == 2) {      
      self(self, now + 1, arr);
    }
    else if (arr[a[now]] == 2) {
      ll bef = arr[b[now]];
      if (bef != 2)
        ans0[now] = true;
      arr[a[now]] = bef;
      arr[b[now]] = 2;
      self(self, now + 1, arr);
      arr[a[now]] = 2;
      arr[b[now]] = bef;
    }
    else if (arr[b[now]] == 0) {
      ll bef = arr[a[now]];
      if(arr[a[now]])
        if (bef != 0)
          ans0[now] = true;
      arr[a[now]] = 0;
      arr[b[now]] = bef;
      self(self, now + 1, arr);
      arr[a[now]] = bef;
      arr[b[now]] = 0;
    }
    else if(arr[a[now]] == 1 && arr[a[now]] == 1) {
      ans0[now] = true;
      arr[a[now]] = 0;
      arr[b[now]] = 0;
      self(self, now + 1, arr);
      arr[a[now]] = 1;
      arr[b[now]] = 2;
      self(self, now + 1, arr);
      arr[b[now]] = 1;
    }
  };

  VL tmp(n, 1);
  dfs(dfs, 0, tmp);
  if (isOk) {
    cout << "Yes\n";
    ll cnt = 0;
    REP(i, m) {
      cnt += !ans0[i];
    }
    cout << cnt << "\n";
    REP(i, m) {
      if (!ans0[i]) {
        cout << i + 1 << " ";
      }
    }
    cout << "\n";
  }
  else {
    cout << "No\n";
    ll cnt = 0;
    REP(i, n) {
      cnt += ans1[i];
    }
    cout << cnt << "\n";
    REP(i, n) {
      if (ans1[i]) {
        cout << i + 1 << " ";
      }
    }
    cout << "\n";

  }
  return;
}

int main() {
  ll t = 1;
  cin >> t;
  while (t--) {
    solve();
  }
  return 0;
}

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