結果

問題 No.3079 Unite Japanese Prefectures
ユーザー 👑 binap
提出日時 2025-02-19 01:13:49
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 3,106 bytes
コンパイル時間 4,730 ms
コンパイル使用メモリ 262,124 KB
実行使用メモリ 10,652 KB
最終ジャッジ日時 2025-03-16 10:23:15
合計ジャッジ時間 39,832 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge2
このコードへのチャレンジ
（要ログイン）
ファイルパターン 結果
sample AC * 1 WA * 2
other AC * 4 WA * 22 TLE * 1
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;

template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}

template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}

random_device seed;
mt19937 mt(seed());
uniform_int_distribution dist(0, 5);

int main(){
	int n, m;
	cin >> n >> m;
	
	vector<tuple<int, int, int>> G;
	
	rep(i, m){
		int u, v, c;
		cin >> u >> v >> c;
		u--; v--; c--;
		G.emplace_back(c, u, v);
	}
	sort(G.begin(), G.end());
	
	atcoder::dsu uf(n);
	vector<int> cnt(6);
	for(auto [c, u, v] : G){
		if(uf.same(u, v)) continue;
		cnt[c]++;
		uf.merge(u, v);
	}
	
	vector<int> zero = {0, 0, 0, 0, 0, 0};
	const int T = 1000000;
	int ans = 0;
	rep(t, T){
		vector<int> cond = cnt;
		int res = 0;
		while(true){
			if(cond == zero) break;
			int dice = dist(mt);
			int MAX = -1;
			for(int i = 0; i <= dice; i++){
				if(cond[i] > 0) MAX = i;
			}
			if(MAX >= 0) cond[MAX]--;
			res++;
		}
		ans += res;
	}
	cout << setprecision(15);
	cout << (long double)ans / T << "\n";
	return 0;
}
0