結果

問題 No.3030 Kruskal-Katona
ユーザー 👑 binap
提出日時 2025-02-21 22:20:07
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 3 ms / 2,000 ms
コード長 3,213 bytes
コンパイル時間 9,876 ms
コンパイル使用メモリ 492,548 KB
実行使用メモリ 6,820 KB
最終ジャッジ日時 2025-02-21 22:20:23
合計ジャッジ時間 10,404 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 27
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return 
    os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); 
    return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return 
    true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder
    ::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 
    1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
#include <boost/multiprecision/cpp_dec_float.hpp>
#include <boost/multiprecision/cpp_int.hpp>
namespace mp = boost::multiprecision;
// 任意長整数型
using Bint = mp::cpp_int;
int main(){
    long long n;
    int i;
    cin >> n >> i;
    
    if(i == 1){
        cout << n << "\n";
        return 0;
    }
    
    if(n <= i){
        vector<int> ans;
        rep(j, n) ans.push_back(i - j);
        cout << ans;
        return 0;
    }
    
    const long long INF = 1001001001;
    
    auto comb = [&](long long p, long long q){
        if(p - q <= q) q = p - q;
        Bint u = 1, d = 1;
        rep(i, q) u *= p - i;
        rep(i, q) d *= i + 1;
        Bint res = u / d;
        if(res >= INF) return INF;
        else return (long long)res;
    };
    
    
    
    vector<int> ans;
    long long prev = INF;
    for(int j = i; j >= 1; j--){
        if(n == 0) break;
        for(long long x = j; x <= prev; x++){
            auto res = comb(x, j);
            if(res > n){
                n -= comb(x - 1, j);
                ans.push_back(x - 1);
                prev = x - 1;
                break;
            }
        }
    }
    cout << ans;
    return 0;
}
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