結果

問題 No.8114 Prime Checker+1
ユーザー smkyb
提出日時 2025-02-23 21:22:44
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 5,676 bytes
コンパイル時間 5,686 ms
コンパイル使用メモリ 426,700 KB
実行使用メモリ 6,820 KB
最終ジャッジ日時 2025-02-23 21:22:52
合計ジャッジ時間 7,157 ms
ジャッジサーバーID
(参考情報)
judge4 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
other AC * 30
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp:140:1: warning: ISO C++ forbids declaration of ‘main’ with no type [-Wreturn-type]
  140 | main(){
      | ^~~~

ソースコード

diff #

#ifdef syssys
#define _GLIBCXX_DEBUG
#endif
#include <bits/stdc++.h>
using namespace std;

using uint = unsigned;
using ull = unsigned long long;
using ll = long long;
using ld = long double;
using lll = __int128;
#define el '\n'
#define all(x) begin(x), end(x)
#define initv2(t,a,...) a, vector<t>(__VA_ARGS__)
#define initv3(t,a,b,...) a, vector<vector<t>>(b, vector<t>(__VA_ARGS__))
#define pair(a,b) pair<a, b>
#define vec vector
#define elif else if
#define pri_q priority_queue
#ifndef syssys
struct fast_io{fast_io(){ios::sync_with_stdio(0); cin.tie(0);}} _fast_io;
#endif

namespace Myb{
    constexpr long long LLINF = 1ll<<62;
    constexpr int INF = 1<<30;
    
    template<typename T, typename U> istream& operator>>(istream& ist, pair<T, U>& p) {cin >> p.first >> p.second; return ist;}
    template<typename T> istream& operator>>(istream& ist, vector<T>& v) {for(T& i : v) cin >> i; return ist;}
    istream& operator>>(istream& ist, _Float128& x) {long double n; cin >> n; x = n; return ist;}
    void read_d_graph(vector<vector<pair<long long, int>>>& v, int m, int num = -1){
        int a, b; long long c;
        for(int _ = 0; _ < m; _++){
            cin >> a >> b >> c;
            a += num; b += num;
            v[a].emplace_back(c, b);
        }
    }
    void read_d_graph(vector<vector<int>>& v, int m, int num = -1){
        int a, b;
        for(int _ = 0; _ < m; _++){
            cin >> a >> b;
            a += num; b += num;
            v[a].emplace_back(b);
        }
    }
    void read_ud_graph(vector<vector<pair<long long, int>>>& v, int m, int num = -1){
        int a, b; long long c;
        for(int _ = 0; _ < m; _++){
            cin >> a >> b >> c;
            a += num; b += num;
            v[a].emplace_back(c, b);
            v[b].emplace_back(c, a);
        }
    }
    void read_ud_graph(vector<vector<int>>& v, int m, int num = -1){
        int a, b;
        for(int _ = 0; _ < m; _++){
            cin >> a >> b;
            a += num; b += num;
            v[a].emplace_back(b);
            v[b].emplace_back(a);
        }
    }
    template<typename T> void read_multi() {}
    template<typename T, typename... U> void read_multi(int n, vector<T>& v, U&&... args){
        if(n < ssize(v)) {cin >> v[n]; read_multi(args..., n+1, v);}
    }
    template<typename T, typename... U> void read_multi(vector<T>& v, U&&... args) {read_multi(args..., 0, v);}
    string input() {string res; cin >> res; return res;}
    long long inputl() {long long res; cin >> res; return res;}
    template<typename T, typename U> ostream& operator<<(ostream& ost, const pair<T, U> p) {cerr << '{'; ost << p.first << ' ' << p.second; cerr << '}'; return ost;}
    template<typename T> ostream& operator<<(ostream& ost, const vector<T>& v) {for(int i = 0; i < ssize(v); i++) {ost << (i ? " " : "") << v[i];} return ost;}
    template<typename T> ostream& operator<<(ostream& ost, const vector<vector<T>>& v) {for(int i = 0; i < ssize(v); i++) {ost << (i ? "\n" : "") << v[i];} return ost;}
    
    long long add_each(long long n) {return n;}
    template<typename T, typename... U> void add_each(long long n, vector<T>& v, U&... args){
        for(auto& i : v) i += n; add_each(n, args...);
    }
    
    template<typename T, typename U> inline bool chmin(T& a, U b) {if(a > b){a = b; return true;} return false;}
    template<typename T, typename U> inline bool chmax(T& a, U b) {if(a < b){a = b; return true;} return false;}
    template<typename T> inline T minv(const vector<T>& v) {return *min_element(v.begin(), v.end());}
    template<typename T> inline T maxv(const vector<T>& v) {return *max_element(v.begin(), v.end());}
    
    long long power(long long val, long long num, long long mod = 0){
        assert(mod >= 0); assert(num >= 0);
        long long res = 1;
        if(mod){
            val %= mod;
            while(num){
                if(num&1) res = (res*val)%mod;
                val = (val*val)%mod;
                num >>= 1;
            }
        } else {
            while(num){
                if(num&1) res = (res*val);
                val = (val*val);
                num >>= 1;
            }
        }
        return res;
    }
    
    long long comb(long long N, long long K, int mod = 0){
        constexpr int COMBSIZ = 200000;
        assert(mod >= 0);
        if(N < K || K < 0) return 0;
        if(mod != 0){
            assert(N <= COMBSIZ);
            static vector<long long> combf(COMBSIZ+9, -1);
            if(combf[0] == -1){
                combf[0] = 1;
                for(long long i = 1; i <= COMBSIZ; i++) combf[i] = (combf[i-1]*i)%mod;
            }
            return (combf[N]*power((combf[N-K]*combf[K])%mod, mod-2, mod))%mod;
        } else {
            long long a=1, b=1;
            K = min(K, N-K);
            for(long long i = N; i > N-K; i--) a *= i;
            for(long long i = 2; i <= K; i++) b *= i;
            return a/b;
        }
    }
} using namespace Myb;

#if __has_include(<atcoder/modint>)
#include <atcoder/modint>
using namespace atcoder;
using mint9 = modint998244353;
using mint1 = modint1000000007;
ostream& operator<<(ostream& ost, const mint1& x) {ost << x.val(); return ost;}
ostream& operator<<(ostream& ost, const mint9& x) {ost << x.val(); return ost;}
#endif
/*vvv^vvvv^vvvvv^^^^^^^^^vv^^^^^^vvvvv^^^vvvvv^^^^^^^^vvvvvvvvv^^^^^^^vvvvvvvvv^^^vv^^^vvvvvvvv^^^^vvvvvv^^vvvvvv^^^^vvv^^^vvvvvvvv^^^vv^^^^^^^vvvvvvvvv^^^^^_^^vvvvvvvv^^^^^^^^vvvv^vvvvvvvvv^^^^^^^v*/



main(){
    
    string s;
    cin >> s;
    if(s == "2") cout << "0\nYes\n";
    else {
        if((s.back()-'0')%2 == 0) cout << "0\nNo\n";
        else cout << "1\nNo\n";
    }
}

0