結果

問題 No.3078 Difference Sum Query
コンテスト
ユーザー 👑 binap
提出日時 2025-02-24 08:44:19
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 685 ms / 2,000 ms
コード長 4,020 bytes
コンパイル時間 4,691 ms
コンパイル使用メモリ 261,820 KB
実行使用メモリ 56,152 KB
最終ジャッジ日時 2025-02-24 22:52:37
合計ジャッジ時間 13,388 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 19
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;

template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}

template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}

// Arranged from
// https://atcoder.jp/contests/abc339/submissions/49979258
struct MergeSortTree{
	int n;
	vector<vector<long long>> a, s;
	bool initialized;
	MergeSortTree(int _n){
		initialized = false;
		n = 1;
		while(n < _n) n <<= 1;
		a.resize(2 * n);
		s.resize(2 * n, vector<long long>{0});
	}
	void set(int i, long long val){
		a[n + i].push_back(val);
		s[n + i].push_back(val);
	}
	void init(){
		initialized = true;
		for(int i = n - 1; i >= 0; i--){
    		int l = (i << 1), r = l + 1;
    		merge(a[l].begin(), a[l].end(), a[r].begin(), a[r].end(), back_inserter(a[i]));
    		s[i].resize(int(a[i].size()) + 1);
    		rep(j, int(a[i].size())) s[i][j + 1] = s[i][j] + a[i][j];
		}
	}
	// [l, r)
	// get #(>= x) - #(<x)
	// get \sigma(>= x) - \sigma(<x)
	
	pair<int, long long> get(int i, long long x) {
		int sz = a[i].size();
		int j = lower_bound(a[i].begin(), a[i].end(), x) - a[i].begin();
		return {(sz - j) - (j - 0), (s[i][sz] - s[i][j]) - (s[i][j] - s[i][0])};
	}
	
	pair<int, long long> query(int l, int r, long long x){
		if(!initialized) init();
		l += n;
		r += n;
		int num = 0;
		long long sum = 0;
		while(l < r){
			if(l & 1){
				auto [num_sub, sum_sub] = get(l, x);
				num += num_sub;
				sum += sum_sub;
				l++;
			}
			if(r & 1){
				r--;
				auto [num_sub, sum_sub] = get(r, x);
				num += num_sub;
				sum += sum_sub;
			}
			l >>= 1;
			r >>= 1;
		}
		return {num, sum};
	}
};

int main(){
	int n, q;
	cin >> n >> q;
	vector<long long> a(n);
	cin >> a;
	
	MergeSortTree mst(n);
	rep(i, n) mst.set(i, a[i]);
	
	rep(_, q){
		int l, r;
		long long x;
		cin >> l >> r >> x;
		l--; r--;
		auto [num, sum] = mst.query(l, r + 1, x);
		long long ans = sum - (long long)num * x;
		cout << ans << "\n";
	}
	
	return 0;
}
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