結果
問題 |
No.2786 RMQ on Grid Path
|
ユーザー |
![]() |
提出日時 | 2025-02-26 01:50:45 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 5,763 ms / 6,000 ms |
コード長 | 2,527 bytes |
コンパイル時間 | 468 ms |
コンパイル使用メモリ | 82,640 KB |
実行使用メモリ | 359,872 KB |
最終ジャッジ日時 | 2025-02-26 01:52:27 |
合計ジャッジ時間 | 101,349 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 35 |
ソースコード
from collections.abc import Iterator def neighbors4(r: int, c: int) -> Iterator[tuple[int, int]]: for dr, dc in [(-1, 0), (1, 0), (0, -1), (0, 1)]: nr = r + dr nc = c + dc if not (0 <= nr < H and 0 <= nc < W): continue yield nr, nc class UnionFind: def __init__(self, n: int): self.data = [-1] * (n+1) self.nexts = [i for i in range(n+1)] def root(self, a: int) -> int: if self.data[a] < 0: return a self.data[a] = self.root(self.data[a]) return self.data[a] def unite(self, a: int, b: int) -> bool: pa = self.root(a) pb = self.root(b) if pa == pb: return False if self.data[pa] > self.data[pb]: pa, pb = pb, pa self.data[pa] += self.data[pb] # pa を pb をつなげる self.data[pb] = pa self.nexts[pa], self.nexts[pb] = self.nexts[pb], self.nexts[pa] return True def issame(self, a: int, b: int) -> bool: return self.root(a) == self.root(b) def size(self, a: int) -> int: """a が属する集合のサイズ""" return -self.data[self.root(a)] def group(self, a: int): """a が属する集合""" yield a x = a while self.nexts[x] != a: x = self.nexts[x] yield x INF = 1 << 60 H, W = map(int, input().split()) G = [] ub = 0 for _ in range(H): G.append(list(map(int, input().split()))) ub = max(ub, max(G[-1])) Q = int(input()) queries = [] for i in range(Q): sr, sc, tr, tc = map(lambda x: int(x)-1, input().split()) s = sr * W + sc t = tr * W + tc queries.append((s, t, i)) conn_map = [[] for _ in range(ub+1)] for i in range(H): for j in range(W): for nr, nc in neighbors4(i, j): h = max(G[i][j], G[nr][nc]) s = i * W + j t = nr * W + nc if s < t: conn_map[h].append((s, t)) lefts = [1] * Q rights = [ub] * Q for _ in range(18): mids = [(a + b) // 2 for a, b in zip(lefts, rights)] h2i = [[] for _ in range(ub+1)] for i in range(Q): h2i[mids[i]].append(i) uf = UnionFind(H * W + 10) for h in range(1, ub+1): for s, t in conn_map[h]: uf.unite(s, t) for qi in h2i[h]: s = queries[qi][0] t = queries[qi][1] if uf.issame(s, t): rights[qi] = h else: lefts[qi] = h for qi in range(Q): ans = rights[qi] print(ans)