結果

問題 No.2740 Old Maid
ユーザー norioc
提出日時 2025-03-04 02:58:07
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 297 ms / 2,000 ms
コード長 2,102 bytes
コンパイル時間 668 ms
コンパイル使用メモリ 82,344 KB
実行使用メモリ 176,888 KB
最終ジャッジ日時 2025-03-04 02:58:26
合計ジャッジ時間 15,738 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 62
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

class Node:
    def __init__(self, val):
        self.val = val
        self.left = None
        self.right = None
class LinkedList:
    def __init__(self):
        self.head = None
        self.tail = None
        self.size = 0
    def __len__(self):
        return self.size
    def __iter__(self):
        if self.head is None: return
        node = self.head
        while node:
            yield node.val
            node = node.right
    @staticmethod
    def _connect(a: Node, b: Node):
        """a と b を接合する"""
        a.right = b
        b.left = a
    def append(self, val) -> Node:
        node = Node(val)
        if self.head is None:
            self.head = self.tail = node
        else:
            LinkedList._connect(self.tail, node)
            self.tail = node
        self.size += 1
        return node
    def appendleft(self, val) -> Node:
        node = Node(val)
        if self.head is None:
            self.head = self.tail = node
        else:
            LinkedList._connect(node, self.head)
            self.head = node
        self.size += 1
        return node
    def remove(self, node: Node):
        assert node is not None
        assert self.size > 0
        if node is self.head:
            self.head = self.head.right
            if self.head:
                self.head.left = None
        elif node is self.tail:
            self.tail = self.tail.left
            if self.tail:
                self.tail.right = None
        else:
            left = node.left
            right = node.right
            left.right = right
            right.left = left
        self.size -= 1
N = int(input())
P = list(map(lambda x: int(x)-1, input().split()))
p2node = {}
ll = LinkedList()
for p in P:
    node = ll.append(p)
    p2node[p] = node
used = set()
ans = []
for i in range(N):
    if i in used: continue
    node = p2node[i]
    if node.right is None: continue
    ans.append(node.val)
    ans.append(node.right.val)
    ll.remove(node)
    ll.remove(node.right)
    used.add(ans[-1])
    used.add(ans[-2])
print(*[x+1 for x in ans])
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