結果
| 問題 |
No.399 動的な領主
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2025-03-06 17:09:04 |
| 言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 4,385 bytes |
| コンパイル時間 | 8,986 ms |
| コンパイル使用メモリ | 357,164 KB |
| 実行使用メモリ | 35,012 KB |
| 最終ジャッジ日時 | 2025-03-06 17:09:30 |
| 合計ジャッジ時間 | 23,737 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 16 WA * 3 |
ソースコード
// #pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
#include <atcoder/all>
// #include <boost/multiprecision/cpp_int.hpp>
using namespace std;
using namespace atcoder;
using mint = modint998244353;
// using mint = modint1000000007;
// using namespace boost::multiprecision;
using uint = unsigned int;
using ll = long long;
// using l3 = __int128;
using ull = unsigned long long;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using T3 = tuple<int, int, int>;
using G = vector<vector<int>>;
#define rep(i, n) for (ll i = 0; i < (n); ++i)
#define rep2(i, a, b) for (ll i = a; i < (b); ++i)
#define rrep2(i, a, b) for (ll i = a-1; i >= (b); --i)
#define rep3(i, a, b, c) for (ll i = a; i < (b); i+=c)
#define rng(a) a.begin(),a.end()
#define rrng(a) a.rbegin(),a.rend()
#define popcount __builtin_popcount
#define popcount_ll __builtin_popcountll
#define fi first
#define se second
#define UNIQUE(v) sort(rng(v)), v.erase(unique(rng(v)), v.end())
#define MIN(v) *min_element(rng(v))
#define MAX(v) *max_element(rng(v))
#define SUM(v) accumulate(rng(v),0LL)
#define IN(v, x) (find(rng(v),x) != v.end())
template<class T> bool chmin(T &a,T b){if(a>b){a=b;return 1;}else return 0;}
template<class T> bool chmax(T &a,T b){if(a<b){a=b;return 1;}else return 0;}
template<class T> void printv(vector<T> &v){rep(i,v.size())cout<<v[i]<<" \n"[i==v.size()-1];}
template<class T> void printvv(vector<vector<T>> &v){rep(i,v.size())rep(j,v[i].size())cout<<v[i][j]<<" \n"[j==v[i].size()-1];cout<<endl;}
const ll dx[] = {-1, 0, 1, 0};
const ll dy[] = {0, 1, 0, -1};
const ll dxx[] = {-1, -1, 0, 1, 1, 1, 0, -1};
const ll dyy[] = {0, 1, 1, 1, 0, -1, -1, -1};
const ll LINF = 3001002003004005006ll;
const int INF = 1001001001;
int rand(){static random_device rd; static mt19937 mt(rd()); static uniform_int_distribution<int> dist(0, INF); return dist(mt);}
pll op(pll a, pll b){return {a.fi+b.fi, a.se+b.se};}
pll e(){return {0, 0};}
pll mapping(ll f, pll x){return {f*x.se+x.fi, x.se};}
ll composition(ll f, ll g){return f+g;}
ll id(){return 0;}
struct HLD {
int n;
vector<vector<int>> g;
vector<int> par, depth, subsize, heavy, head, pos;
int cur;
// add here (segtree, fenwicktree..)
lazy_segtree<pll, op, e, ll, mapping, composition, id> seg;
HLD(int _n) : n(_n), g(_n), par(_n, -1), depth(_n, 0),
subsize(_n, 0), heavy(_n, -1), head(_n), pos(_n), cur(0), seg(_n){
rep(i, n) seg.set(i, {0,1});
}
void add_edge(int u, int v) {
g[u].push_back(v);
g[v].push_back(u);
}
int dfs(int v, int p=-1) {
par[v] = p;
subsize[v] = 1;
int max_subtree = 0;
for (auto u: g[v]) if (u != p){
depth[u] = depth[v] + 1;
int sz = dfs(u, v);
if (sz > max_subtree){
max_subtree = sz;
heavy[v] = u;
}
subsize[v] += sz;
}
return subsize[v];
}
void decompose(int v, int h) {
head[v] = h;
pos[v] = cur++;
if (heavy[v] != -1) {
decompose(heavy[v], h);
}
for (auto u : g[v]) {
if (u == par[v] || u == heavy[v]) continue;
decompose(u, u);
}
}
void build(int root=0) {
dfs(root);
decompose(root, root);
}
int solve(int u, int v) {
ll res = 0;
while (head[u] != head[v]) {
if (depth[head[u]] < depth[head[v]]) swap(u, v);
int L = pos[head[u]], R = pos[u]+1; // [L, R)
seg.apply(L, R, 1);
res += seg.prod(L, R).fi;
u = par[head[u]];
}
if (depth[u] < depth[v]) swap(u, v);
int L = pos[v], R = pos[u]+1;
seg.apply(L, R, 1);
res += seg.prod(L, R).fi;
cerr << L << " " << R << endl;
cerr << res << endl;
return res;
}
};
int main(){
ios::sync_with_stdio(false);
cin.tie(nullptr);
int n; cin >> n;
HLD g(n);
rep(i, n-1){
int u, v; cin >> u >> v; u--, v--;
g.add_edge(u, v);
}
g.build();
int q; cin >> q;
ll ans = 0;
rep(qi, q){
int u, v; cin >> u >> v; u--, v--;
ans += g.solve(u, v);
assert(ans <= 500005000000000);
}
cout << ans << endl;
return 0;
}