結果
問題 |
No.2209 Flip and Reverse
|
ユーザー |
![]() |
提出日時 | 2025-03-20 18:46:50 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 358 ms / 2,000 ms |
コード長 | 1,572 bytes |
コンパイル時間 | 206 ms |
コンパイル使用メモリ | 82,500 KB |
実行使用メモリ | 272,104 KB |
最終ジャッジ日時 | 2025-03-20 18:47:43 |
合計ジャッジ時間 | 9,920 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 30 |
ソースコード
n = int(input()) s = input().strip() t = input().strip() def compute_min_steps(s, t_target, reversed_t): delta = [] for i in range(n): delta.append(int(s[i] != t_target[i])) c1 = 0 c3 = 0 cmid = 0 # Process mirror pairs processed = [False] * n for x in range(n): y = n - 1 - x if x >= y: break processed[x] = processed[y] = True dx = delta[x] dy = delta[y] if dx == dy: if dx == 0: pass # c0 +=1 else: c3 +=1 # contributes 2 steps, adds 1 to both groups else: c1 +=1 # contributes 1 step, allocated to group A or B # Check middle element if n % 2 == 1: mid = n // 2 if delta[mid] == 1: cmid +=1 return (c3, c1, cmid) # Case even m: target is T reversed_t_even = list(t) c3_even, c1_even, cmid_even = compute_min_steps(s, reversed_t_even, False) steps_even = 2 * c3_even + c1_even + cmid_even valid_even = False if (c1_even + cmid_even) % 2 == 0 and steps_even % 2 == 0: valid_even = True # Case odd m: target is reversed T reversed_t_odd = list(t[::-1]) c3_odd, c1_odd, cmid_odd = compute_min_steps(s, reversed_t_odd, True) steps_odd = 2 * c3_odd + c1_odd + cmid_odd valid_odd = False if (c1_odd + cmid_odd) % 2 == 1 and steps_odd % 2 == 1: valid_odd = True candidates = [] if valid_even: candidates.append(steps_even) if valid_odd: candidates.append(steps_odd) if len(candidates) == 0: print(-1) else: print(min(candidates))