結果
問題 | No.1418 Sum of Sum of Subtree Size |
ユーザー |
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提出日時 | 2025-03-20 18:51:13 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 249 ms / 2,000 ms |
コード長 | 1,184 bytes |
コンパイル時間 | 251 ms |
コンパイル使用メモリ | 82,108 KB |
実行使用メモリ | 102,920 KB |
最終ジャッジ日時 | 2025-03-20 18:52:49 |
合計ジャッジ時間 | 7,362 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 41 |
ソースコード
import syssys.setrecursionlimit(1 << 25)n = int(sys.stdin.readline())edges = [[] for _ in range(n + 1)]for _ in range(n - 1):a, b = map(int, sys.stdin.readline().split())edges[a].append(b)edges[b].append(a)sum_edges = 0size = [0] * (n + 1)# Using iterative post-order traversal to compute sizes and sum_edgesstack = []stack.append((1, -1, False)) # (node, parent, visited)while stack:node, parent, visited = stack.pop()if not visited:# Push back the node as visited after processing childrenstack.append((node, parent, True))# Add children in reverse order to process them in orderfor child in reversed(edges[node]):if child != parent:stack.append((child, node, False))else:# Calculate the size of the current nodes = 1for child in edges[node]:if child != parent:s += size[child]size[node] = s# Add contribution for each child edgefor child in edges[node]:if child != parent:sum_edges += size[child] * (n - size[child])ans = 2 * sum_edges + n * nprint(ans)