結果
| 問題 | No.1418 Sum of Sum of Subtree Size | 
| コンテスト | |
| ユーザー |  lam6er | 
| 提出日時 | 2025-03-20 18:51:13 | 
| 言語 | PyPy3 (7.3.15) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 249 ms / 2,000 ms | 
| コード長 | 1,184 bytes | 
| コンパイル時間 | 251 ms | 
| コンパイル使用メモリ | 82,108 KB | 
| 実行使用メモリ | 102,920 KB | 
| 最終ジャッジ日時 | 2025-03-20 18:52:49 | 
| 合計ジャッジ時間 | 7,362 ms | 
| ジャッジサーバーID (参考情報) | judge2 / judge3 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 3 | 
| other | AC * 41 | 
ソースコード
import sys
sys.setrecursionlimit(1 << 25)
n = int(sys.stdin.readline())
edges = [[] for _ in range(n + 1)]
for _ in range(n - 1):
    a, b = map(int, sys.stdin.readline().split())
    edges[a].append(b)
    edges[b].append(a)
sum_edges = 0
size = [0] * (n + 1)
# Using iterative post-order traversal to compute sizes and sum_edges
stack = []
stack.append((1, -1, False))  # (node, parent, visited)
while stack:
    node, parent, visited = stack.pop()
    if not visited:
        # Push back the node as visited after processing children
        stack.append((node, parent, True))
        # Add children in reverse order to process them in order
        for child in reversed(edges[node]):
            if child != parent:
                stack.append((child, node, False))
    else:
        # Calculate the size of the current node
        s = 1
        for child in edges[node]:
            if child != parent:
                s += size[child]
        size[node] = s
        # Add contribution for each child edge
        for child in edges[node]:
            if child != parent:
                sum_edges += size[child] * (n - size[child])
ans = 2 * sum_edges + n * n
print(ans)
            
            
            
        