結果

問題 No.1390 Get together
ユーザー lam6er
提出日時 2025-03-20 18:51:35
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 572 ms / 2,000 ms
コード長 1,847 bytes
コンパイル時間 174 ms
コンパイル使用メモリ 82,760 KB
実行使用メモリ 184,028 KB
最終ジャッジ日時 2025-03-20 18:53:00
合計ジャッジ時間 10,875 ms
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 29
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
from collections import defaultdict
class UnionFind:
def __init__(self, size):
self.parent = list(range(size + 1)) # 1-based indexing
self.rank = [0] * (size + 1)
def find(self, x):
if self.parent[x] != x:
self.parent[x] = self.find(self.parent[x])
return self.parent[x]
def union(self, x, y):
x_root = self.find(x)
y_root = self.find(y)
if x_root == y_root:
return
if self.rank[x_root] < self.rank[y_root]:
self.parent[x_root] = y_root
else:
self.parent[y_root] = x_root
if self.rank[x_root] == self.rank[y_root]:
self.rank[x_root] += 1
def main():
input = sys.stdin.read().split()
ptr = 0
N = int(input[ptr])
ptr += 1
M = int(input[ptr])
ptr += 1
color_b = defaultdict(set) # color c -> set of boxes
box_c = defaultdict(set) # box b -> set of colors
for _ in range(N):
b = int(input[ptr])
ptr += 1
c = int(input[ptr])
ptr += 1
color_b[c].add(b)
box_c[b].add(c)
# Initialize Union-Find for colors up to N
uf = UnionFind(N)
# Connect all colors within the same box
for b in box_c:
colors = list(box_c[b])
if len(colors) < 2:
continue
root = colors[0]
for c in colors[1:]:
uf.union(root, c)
# Count the number of boxes per group
counter = defaultdict(int)
for b in box_c:
colors = box_c[b]
# Get any color in the box and find its root
c = next(iter(colors))
root = uf.find(c)
counter[root] += 1
# Calculate the answer
ans = sum(k - 1 for k in counter.values())
print(ans)
if __name__ == '__main__':
main()
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