結果
問題 |
No.2402 Dirty Stairs and Shoes
|
ユーザー |
![]() |
提出日時 | 2025-03-20 18:59:53 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 130 ms / 2,000 ms |
コード長 | 1,896 bytes |
コンパイル時間 | 315 ms |
コンパイル使用メモリ | 82,320 KB |
実行使用メモリ | 111,192 KB |
最終ジャッジ日時 | 2025-03-20 19:00:33 |
合計ジャッジ時間 | 4,331 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 32 |
ソースコード
import sys from collections import deque def main(): n, K = map(int, sys.stdin.readline().split()) m1 = int(sys.stdin.readline()) a_list = list(map(int, sys.stdin.readline().split())) if m1 > 0 else [] dirty = set(a_list) m2 = int(sys.stdin.readline()) b_list = list(map(int, sys.stdin.readline().split())) if m2 > 0 else [] mat = set(b_list) # Visited arrays for clean and dirty states visited_clean = [False] * (n + 1) visited_dirty = [False] * (n + 1) queue = deque() queue.append((0, True)) visited_clean[0] = True found = False while queue: p, is_clean = queue.popleft() for move in [1, K]: next_p = p + move if next_p > n: continue # Check if next_p is the target N if next_p == n: # The new state is same as current since N is neither dirty nor mat if is_clean: found = True break else: continue else: # Determine the new state based on next_p's type if next_p in dirty: new_clean = False elif next_p in mat: new_clean = True else: new_clean = is_clean # Check if this state has been visited before if new_clean: if not visited_clean[next_p]: visited_clean[next_p] = True queue.append((next_p, new_clean)) else: if not visited_dirty[next_p]: visited_dirty[next_p] = True queue.append((next_p, new_clean)) if found: break print("Yes" if found else "No") if __name__ == "__main__": main()