結果
| 問題 |
No.1418 Sum of Sum of Subtree Size
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-03-20 20:23:12 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 240 ms / 2,000 ms |
| コード長 | 1,184 bytes |
| コンパイル時間 | 259 ms |
| コンパイル使用メモリ | 82,312 KB |
| 実行使用メモリ | 103,016 KB |
| 最終ジャッジ日時 | 2025-03-20 20:25:19 |
| 合計ジャッジ時間 | 7,098 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 41 |
ソースコード
import sys
sys.setrecursionlimit(1 << 25)
n = int(sys.stdin.readline())
edges = [[] for _ in range(n + 1)]
for _ in range(n - 1):
a, b = map(int, sys.stdin.readline().split())
edges[a].append(b)
edges[b].append(a)
sum_edges = 0
size = [0] * (n + 1)
# Using iterative post-order traversal to compute sizes and sum_edges
stack = []
stack.append((1, -1, False)) # (node, parent, visited)
while stack:
node, parent, visited = stack.pop()
if not visited:
# Push back the node as visited after processing children
stack.append((node, parent, True))
# Add children in reverse order to process them in order
for child in reversed(edges[node]):
if child != parent:
stack.append((child, node, False))
else:
# Calculate the size of the current node
s = 1
for child in edges[node]:
if child != parent:
s += size[child]
size[node] = s
# Add contribution for each child edge
for child in edges[node]:
if child != parent:
sum_edges += size[child] * (n - size[child])
ans = 2 * sum_edges + n * n
print(ans)
lam6er