結果
| 問題 | No.1859 ><<< |
| ユーザー |
lam6er
|
| 提出日時 | 2025-03-20 20:30:34 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 203 ms / 2,000 ms |
| コード長 | 1,801 bytes |
| 記録 | |
| コンパイル時間 | 324 ms |
| コンパイル使用メモリ | 82,240 KB |
| 実行使用メモリ | 173,896 KB |
| 最終ジャッジ日時 | 2025-03-20 20:31:10 |
| 合計ジャッジ時間 | 10,560 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 41 |
ソースコード
def compute_prefix_function(pattern):
m = len(pattern)
prefix = [0] * m
k = 0 # length of the previous longest prefix suffix
for q in range(1, m):
while k > 0 and pattern[k] != pattern[q]:
k = prefix[k-1]
if pattern[k] == pattern[q]:
k += 1
prefix[q] = k
return prefix
def kmp_search(text, pattern, prefix):
n = len(text)
m = len(pattern)
q = 0 # current index in pattern
positions = []
for i in range(n):
while q > 0 and pattern[q] != text[i]:
q = prefix[q-1]
if pattern[q] == text[i]:
q += 1
if q == m:
positions.append(i - m + 1)
q = prefix[q-1] # look for next possible match
return positions
def main():
import sys
input = sys.stdin.read().split()
idx = 0
N = int(input[idx])
idx += 1
A = list(map(int, input[idx:idx+N]))
idx += N
S = input[idx].strip()
if len(S) != N-1:
print(-1)
return
# Generate the 'rel' array
rel = []
for i in range(N):
j = (i + 1) % N
if A[i] < A[j]:
rel.append('<')
else:
rel.append('>')
# Text is rel concatenated twice
T = rel + rel
# Check if pattern is longer than N-1
pattern = list(S)
m = len(pattern)
if m != N-1:
print(-1)
return
# Compute prefix function for KMP
prefix = compute_prefix_function(pattern)
# Find all occurrences of pattern in T
positions = kmp_search(T, pattern, prefix)
# Check valid k (0 <= k < N)
valid_ks = [k for k in positions if 0 <= k < N]
if valid_ks:
print(min(valid_ks))
else:
print(-1)
if __name__ == '__main__':
main()
lam6er