結果
| 問題 |
No.2428 Returning Shuffle
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-03-20 20:38:27 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,550 bytes |
| コンパイル時間 | 170 ms |
| コンパイル使用メモリ | 82,512 KB |
| 実行使用メモリ | 272,564 KB |
| 最終ジャッジ日時 | 2025-03-20 20:38:53 |
| 合計ジャッジ時間 | 6,943 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 18 WA * 5 |
ソースコード
import sys
def main():
MOD = 998244353
input = sys.stdin.read().split()
ptr = 0
n, m = int(input[ptr]), int(input[ptr+1])
ptr += 2
cycles = []
for _ in range(m):
t = int(input[ptr])
s = list(map(int, input[ptr+1:ptr+1+t]))
ptr += 1 + t
cycles.append(s)
# Initialize permutation F as identity
F = list(range(n + 1)) # 1-based indexing
# Process each cycle in reverse order
for s in reversed(cycles):
k = len(s)
# Create next_s for each element in the cycle
next_s = [0] * k
for i in range(k):
next_s[i] = s[(i+1) % k]
# Generate the temporary values
temp = []
for i in range(k):
temp.append(F[next_s[i]])
# Update F for each element in s
for i in range(k):
F[s[i]] = temp[i]
# Find the cycle decomposition of F
visited = [False] * (n + 1)
lcm = 1
for i in range(1, n+1):
if not visited[i]:
length = 0
j = i
while not visited[j]:
visited[j] = True
j = F[j]
length += 1
# Compute LCM of lcm and length
def gcd(a, b):
while b:
a, b = b, a % b
return a
current_gcd = gcd(lcm, length)
lcm = (lcm // current_gcd) * length
lcm %= MOD # Since LCM can be large, mod by MOD
print(lcm % MOD)
if __name__ == "__main__":
main()
lam6er